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Unit 19: Cyclic Subspaces and Annihilators
T-cyclic Subspace Notes
If is any vector in V, the T-cyclic subspace generated by is the subspace Z(; T) of all vectors
of the form g(T), g in F[x]. If Z(; T) = V, then is called a cyclic vector for T.
K
In other words, the subspace Z(; T) is the subspace spanned by the vectors T , K 0 and thus
is a cyclic vector for T if and only if these vectors span V.
Example 1: For any T, the T-cyclic subspace generated by the zero vector is the zero
space.
If the vector is a characteristic vector for T the space Z(; T) is one dimensional.
For the identity operator, every non-zero vector generates a one dimension cyclic subspace,
thus, if dim V > 1, the identity operator has no cyclic vector.
2
Example 2: Consider the linear operator T on F which is represented in the standard
basis by the matrix
0 0
A
1 0
Here the cyclic vector is = (1, 0); for
1
A =
1 2
So that for any vector given by
(a, b)
We have (a, b) = a + b ,
1 2
so = a + bA
1 1
= (a + bA)
1
2
Thus the polynomial g in F (x) can be taken as
g = a + bx
For the same operator T, the cyclic subspace generated by = (0, 1) is the one dimensional space
2
spanned by , because is a characteristic vector of T.
2 2
3
Example 3: Consider the linear operator T on F , which is represented by A;
0 1 0
A 1 0 1
0 1 0
Here A = 0, but A 0. So if is a vector such that A 0 i.e., = = (1,0,0), then the basic
2
2
3
1
vectors will be (, T, T ) and space generated by is a cyclic subspace.
2
1
19.2 Annihilators
For any T and , we shall be interested in linear relations
k
c + c T + ... + c T = 0
0 1 k
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