Page 215 - DMTH502_LINEAR_ALGEBRA
P. 215
Unit 19: Cyclic Subspaces and Annihilators
i–1
polynomial for U (and hence also the characteristic polynomial for U). If we let = U , i = Notes
i
1,..., k, then the action of U on the ordered basis = { ,..., } is
1 k
U i 1 , i 1,...,k
1
i
... (1)
c
c
U ... c
k 0 1 1 2 k 1 k
...
k
where p = c + c x + + c x + x . The expression for U follows from the fact that p (U) = 0,
k–1
0 1 k–1 k
i.e.,
...
U + c U + + c U + c = 0
k–1
k
k–1 1 0
This says that the matrix of U in the ordered basis is
0 0 0 0 c 0
1 0 0 0 c
1
0 1 0 0 c
2
0 0 0 1 c
k 1
The matrix (2) is called the companion matrix of the monic polynomial p .
Theorem 2: If U is a linear operator on the finite-dimensional space W, then U has a cyclic vector
if and only if there is some ordered basis for W in which U is represented by the companion
matrix of the minimal polynomial for U.
Proof: We have just observed that if U has a cyclic vector, then there is such an ordered basis for
W. Conversely, if we have some ordered basis { ,..., } for W in which U is represented by the
1 k
companion matrix of its minimal polynomial, it is obvious that is a cyclic vector for U.
1
Corollary: If A is the companion matrix of a monic polynomial p, then p is both the minimal and
the characteristic polynomial of A.
Proof: One way to see this is to let U be the linear operator on F which is represented by A in the
k
standard ordered basis, and to apply Theorem 1 together with the Cayley-Hamilton theorem.
Another method is to use Theorem 1 to see that p is the minimal polynomial for A and to verify
by a direct calculation that p is the characteristic polynomial for A.
One last comment—if T is any linear operator on the space V and is any vector in V, then the
operator U which T induces on the cyclic subspace Z(; T) has a cyclic vector, namely, . Thus
Z(; T) has an ordered basis in which U is represented by the companion matrix of p , the
T-annihilator of .
Self Assessment
1. Consider the linear operator T represented by the matrix
1 1 1
A 1 1 1
1 1 0
Show that A is nilpotent. Find the basis vectors that will span the space of the linear
operator T.
2. Let T be a linear operator on the finite dimensional vector space V. Suppose T has a cyclic
vector. Prove that if U is any linear operator which commutes with T, then U is a
polynomial in T.
LOVELY PROFESSIONAL UNIVERSITY 209