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Unit 19: Cyclic Subspaces and Annihilators




                                                                                 i–1
          polynomial for U (and hence also the characteristic polynomial for  U). If we let  = U , i =  Notes
                                                                             i
          1,..., k, then the action of U on the ordered basis  = { ,...,  } is
                                                      1   k
                                       U   i 1 ,  i  1,...,k  
                                                              1
                                          i
                                                                                  ... (1)
                                             c
                                                         
                                                  c
                                       U        ... c 
                                          k   0  1  1  2   k 1  k 
                           ...
                                     k
          where p  = c  + c x +   + c x  + x . The expression for U  follows from the fact that p (U) = 0,
                                 k–1
                   0  1       k–1                      k                      
          i.e.,
                                                ...
                                  U  + c U  +   + c U + c  = 0
                                           k–1
                                    k
                                        k–1         1     0
          This says that the matrix of U in the ordered basis  is
                                        0 0 0    0   c   0 
                                        1 0 0    0   c   
                                                       1  
                                        0 1 0    0   c 
                                                        2
                                                        
                                                    
                                        0 0 0    1  c  
                                                      k 1
          The matrix (2) is called the companion matrix of the monic polynomial p .
                                                                     
          Theorem 2: If U is a linear operator on the finite-dimensional space W, then U has a cyclic vector
          if and only if there is some ordered basis for  W in which U is represented by the companion
          matrix of the minimal polynomial for U.
          Proof: We have just observed that if U has a cyclic vector, then there is such an ordered basis for
          W. Conversely, if we have some ordered basis { ,...,  } for W in which U is represented by the
                                                 1    k
          companion matrix of its minimal polynomial, it is obvious that   is a cyclic vector for U.
                                                               1
          Corollary: If A is the companion matrix of a monic polynomial p, then p is both the minimal and
          the characteristic polynomial of A.
          Proof: One way to see this is to let U be the linear operator on F  which is represented by A in the
                                                            k
          standard ordered basis, and to apply Theorem 1 together with the Cayley-Hamilton theorem.
          Another method is to use Theorem 1 to see that p is the minimal polynomial for A and to verify
          by a direct calculation that p is the characteristic polynomial for A.
          One last comment—if T is any linear operator on the space V and  is any vector in V, then the
          operator U which T induces on the cyclic subspace Z(; T) has a cyclic vector, namely, . Thus
          Z(; T) has an ordered basis in which  U is represented by the companion matrix of  p , the
                                                                                  
          T-annihilator of .
          Self Assessment

          1.   Consider the linear operator T represented by the matrix

                           1  1  1 
                                  
                      A   1  1  1 
                         
                           1  1  0 
                                  
               Show that  A is nilpotent. Find the basis vectors that will span the space of the linear
               operator T.
          2.   Let T be a linear operator on the finite dimensional vector space V. Suppose T has a cyclic
               vector. Prove  that if  U is  any linear  operator  which  commutes with  T,  then  U  is  a
               polynomial in T.




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