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P. 300
Linear Algebra
Notes If we multiply the second equation by i and add the result to the first equation, we obtain
2f( , ) = 2f( , ).
Corollary: Let T be a linear operator on a complex finite-dimensional inner product space V.
Then T is self-adjoint if and only if (T | ) is real for every in V.
Theorem 4 (Principal Axis Theorem): For every Hermitian form f on a finite-dimensional inner
product space V, there is an orthonormal basis of V in which f is represented by a diagonal
matrix with real entries.
Proof: Let T be the linear operator such that f( , ) = (T | ) for all and in V. Then, since
f( , ) = ( , )f and (T | ) ( |T ) , it follows that
(T | ) = ( , ) ( |f T )
for all and ; hence T = T*. By Theorem 5 of unit 24, there is an orthonormal basis of V which
consists of characteristic vectors for T. Suppose { , ..., } is an orthonormal basis and that
1 n
T = c
j j j
for 1 j n. Then
f( , ) = (T | ) = c
k j k j kj k
and by Theorem 2 of unit 24 each c is real.
k
Corollary: Under the above conditions
( f x j j , y k k ) = c x y
j j j
j k j
Self Assessment
1. Which of the following functions f, defined on vectors = (x , x ) and (y , y ) = in c , are
2
1 2 1 2
sesquilinear forms on c 2
(a) f( , ) = (x – y ) + x y
2
1 1 2 2
(b) f( , ) = x y – x y
2 2 1
(c) f( , ) = x y
1 1
2. Let f be a non-degenerate form on a finite-dimensional space V. Show that each linear
operator S has an ‘adjoint’ relative to f’, i.e., an operator S’ such that f(S , ) = f( , S’ ) for
all , .
27.3 Summary
In the introduction a review of the last units 24, 25, 26 is done. It is stated that the ideas
covered in these units are fundamental.
In this unit forms on inner product space are studied and the relation between the forms
and the linear operator is established.
A sesquilinear form is introduced and explained for all , , in the finite vector space V
and its relation with the linear operators.
When the basis is an orthonormal basis, the matrix of the form f in is also matrix of the
linear transformation T .
fi
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