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Unit 28: Positive Forms and More on Forms




          28.2 More on Forms                                                                    Notes

          Theorem 3: Let f be a form on a real or complex vector space V and { , ...,  } a basis for the finite
                                                                 1    r
          dimensional subspace W of V. Let M be the r   r matrix with entries
                                    M = f( ,  )
                                     jk    k  j
          and W’ the set of all vectors   in V such that f( ,  ) for all   in W. Then W’ is subspace of V, and
          W   W’ = {0} if and only if M is invertible. When this is the case, V = W + W’.

          Proof: If   and   are vectors in W’ and c is a scalar, then for every   in W
                              f( , c  +  ) =   c f( ,  ) + f( ,  )
                                       = 0.

          Hence, W’ is a subspace of V.
                          r                 r
          Now suppose   =   x x k  and that   =   y j  j . Then
                         k  1              j  1

                                          r
                                 f( ,  ) =   , y M x
                                               jk k
                                          , j k

                                       =      y M jk  x  . k
                                               j
                                         k   j
          It follows from this that W   W’   {0} if and only if the homogeneous system
                               r
                                 y M jk = 0, 1   k   r
                                  j
                               j  1
          has a non-trivial solution (y  ..., y ). Hence W   W‘ {0} if and only if M* is invertible. But the
                                 1   r
          invertibility of M* is equivalent to the invertibility of M.
          Suppose that M is invertible and let

                                                  –1
                                            –1
                                     A = (M*)  = (M )*
                                          r
                                   g ( ) =   A jk  ( f  k  , )
                                    j
                                         k  1
          Then
                               g (c  +  ) =   kn  ( f  k  , c  )
                                j
                                         k
                                       =  c  A jk  ( f  k , )  A jk  ( f  k  , )
                                          k            k
                                       = cg ( ) + g ( )
                                          j     j
          Hence, each g  is a linear function on V. Thus we may define a linear operator E on V by setting
                     j
                                          r
                                    E  =    g j ( )  j
                                         j  1







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