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Unit 28: Positive Forms and More on Forms




          Proof: Since  (A*) =   k ( )  (1   k   n ), the principal minors of A are all different from 0. Hence,  Notes
                              A
                     k
          by the lemma used in the proof of Theorem 2, there exists an upper-triangular matrix  P with
          P  = 1 such that A*P is lower-triangular. Therefore, P*A = (A*P)* is upper-triangular. Since the
           kk
          product of  two upper-triangular matrices is again upper  triangular, it  follows that  P*AP  is
          upper-triangular. This shows the existence but not the uniqueness of P. However, there is another
          more geometric argument which may be used to prove both the existence and uniqueness of P.
          Let W  be the subspace spanned by  , ...,   and W’  the set of all   in V such that f( ,  ) = 0 for
               k                        1    k     k
          every   in W . Since  (A)   0, the k   k matrix M with entries
                     k      k
                                    M = f( ,  ) = A
                                      ij   j  i  ij
          (1   i, j   k) is invertible. By Theorem 3

                                     V = W    W’ .
                                          k    k
          Let E  be the projection of V on W  which is determined by this decomposition, and set E  = 0. Let
              k                     k                                           0
                                       =   – E  ,    (1   k   n)
                                      k   k  k –1  k
          Then   =  , and E   belongs to W  for k > 1. Thus when k > 1, there exist unique scalars P  such
                1  1     k–1  k       k–1                                         jk
          that
                                          k  1
                                  E    = –  P jk  j
                                   k –1  k
                                          j  1
          Setting P  = 1 and P  = 0 for j < k, we then have an  n × n upper triangular matrix P with P  = 1 and
                 kk       jk                                                   kk
                                          k
                                     B =   P jk  j
                                      k
                                         j  1
          for k =1, ..., n. Suppose 1    i   k. Then B  is in W    W  since B  belongs to W’ , it follows that
                                          k      i   k–1     k           k –1
          f( ,  ) = 0. Let B denote the matrix of f in the ordered basis ( , ...  ). Then
            i  k                                            1   n
                                    B = f( ,  )
                                     ki    i  k
          so B  = 0 when k > i. Thus B is upper-triangular. On the other hand,
             ki
                                     B = P*AP.

          Self Assessment

          1.   Which of the following matrices are positive?

                                 1  1 1    1  1 2 1 3
                1 2    1   1 i
                     ,         , 2  1 1 , 1 2 1 2 1 4
                3 4   1 i   3
                                 3  1 1   1 3 1 4 1 5
          2.   Prove  that the product of two positive linear operators  is positive if and only if  they
               commute.

          3.   Let S and T be positive operators. Prove that every characteristic value of ST is positive.

          28.3 Summary

              In this unit we are studying the form f on a finite vector space being non-negative.
              We obtain certain equivalent properties and show that when the matrix A of linear operator
               is Hermitian i.e. A + A* as well as the principal minors of the matrix A are all positive.



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