Page 171 - DMTH503_TOPOLOGY
P. 171

Unit 18: Normal Spaces, Regular Spaces and Completely Regular Spaces




          bound of the set of distances d(x, a) from x to points a  A. Note that d(x, A)  0, and d(x, A) = 0  Notes
          iff x is in the closure of A since d(X, A) = 0 is equivalent to saying that every ball B (x) contains
                                                                             r
          points of A.

                 Example 2: A compact Hausdorff space is normal.

          Solution: Let A and B be disjoint closed sets in a compact Hausdorff space X. In particular, this
          implies  that A and B are compact since they are closed subsets of a compact space. By the
          argument in the proof of the preceding example we know that for each x  A,  disjoint open sets
             and V  with x    and B  V . Letting x very over A, we have an open cover of A by the sets  .
           x     x        x        x                                                 x
          So, there is a finite subcover. Let   be the union of the sets   in this finite subcover and let V be
                                                          x
          the intersection of the corresponding sets V . Then   and V are disjoint open nhds. of A and B.
                                             x
                 Example 3: A closed sub-space of a normal space is a normal space.
          Solution: Let (X, T) be a topological space which is normal and (Y,  ) a closed sub-space of (X, T)
          so that Y is closed in X. To prove that Y is a normal space.
          Let F , F   Y be disjoint sets which are closed in Y. Y is closed in X, a subset F of Y is closed in Y
              1  2
          iff F is closed in X.
           F  and F  are disjoint closed sets in X.
             1     2
          By the property of normal space (X, T).

                    G , G   T s.t. F   G , F   G , G    G  = 
                      1  2       1   1  2   2  1   2
                       F   G   F   Y  G   Y  F  = F   Y  G   Y
                        1   1    1      1       1   1       1
                              F   G   Y.
                                 1   1
          Similarly F   G   F   G   Y.
                   2   2    2   2
          By definition of relative topology,
                     G , G   T  Y  G , Y  G  
                      1  2           1     2
          Also (G   Y)  (G   Y) = (Y  Y)  (G   G ) = Y   = .
                1        2                1   2
          Finally given a pair of disjoint closed sets F , F  in Y,  disjoint sets.
                                             1  2
                G   Y, G   Y    s.t. F   G   Y, F   G   Y.
                 1      2          1    1     2   2
          This proves that (Y,  ) is a normal space.

          Self Assessment


          1.   Show that if X is normal, every pair of disjoint closed sets have neighborhoods whose
               closures are disjoint.
          2.   Give an example of a normal space with a subspace that is not normal.

          3.   Show that paracompact space (X, T) is normal.

          18.2 Regular Space

          A topological space (X, T) is said to be regular space if: given an element x  X and closed set
          F  X s.t. x  F,  disjoint open sets G , G   X s.t. x  G , F  G .
                                        1  2           1     2



                                           LOVELY PROFESSIONAL UNIVERSITY                                   165
   166   167   168   169   170   171   172   173   174   175   176