Page 174 - DMTH503_TOPOLOGY
P. 174
Topology
Notes Theorem 2: Prove that a normal space is a regular space i.e. to say, X is a T -space X is a T -space.
4 3
Proof: Let (X, T) be a T -space so that
4
(i) X is a T -space
1
(ii) X is a regular space
To prove that X is a T -space. For this we must show that
3
(iii) X is a T -space
1
(iv) X is a regular space
Evidently (i) (iii)
If we show that (ii) (iv), the result will follow. Let F X be a closed set and x X s.t. x F.
X is a T -space {x} is closed in X.
1
By normality, given a pair of disjoint closed sets {x} and F in X, disjoint open sets G, H in X s.t.
{x} G, F X, i.e. given a closed set F X and x X s.t. x F. disjoint open sets G, H in X s.t.
{x} G, F H. This proves that (X, T) is a regular space.
Example 6: Show that the property of a space being regular is hereditary property.
Solution: Let (Y, ) be a subspace of a regular space (X, T). We claim that the property of regularity
is hereditary property. If we show that (Y, ) is regular, the result will follow.
Let F be a -closed set and p Y s.t. p F.
È
T
Let F = closure of F w.r.t. the topology T. and F = closure of F w.r.t. the topology we know
È
T
that F = F Y.
T
È
Since F is a -closed set F = F F = F Y.
T
T
p F p F Y p F or p Y
T
p F for p Y.
T
F is a T-closed set.
closure of any set is always closed.
T
T
By the regularity of (X, T), given a closed set F and a point p X. s.t. p F ; disjoint sets G,
T
H T with p G, F H.
T
Consequently, F = F Y H Y, p G Y
(G Y) (H Y) = (G H) (Y Y) = Y =
Thus, we have shown that given a -closed set F and a point p Y s.t. p F, we are able to find
out the disjoint open sets G Y, H Y in Y s.t. p G Y, F H Y.
This proves that (Y, ) is regular. Hence proved.
Self Assessment
4. Show that the usual topological space (R, È) is regular.
5. Show that every T -space is a T -space.
3 2
168 LOVELY PROFESSIONAL UNIVERSITY