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Unit 22: The Tychonoff Theorem




                                                                                                Notes
                 Example 1: Let X be a topological space and let  be a closed sub-base for X and let {B } be
                                                                                   i
          its generated closed base i.e. the class of all finite union of members of  if every class of B ’s with
                                                                                 i
          the finite intersection property (FIP) has a non-empty intersection then X is compact.
          Solution: Under the given hypothesis, we shall prove that X is compact. In order to prove the
          required result it is sufficient to show that every basic cover of X has a finite sub-cover.
          Let {O} be any basic open cover of X. Then X =  O .
               j                                   j
                                                 j
                                                                             C
                 C
          Now, { B } being an open base for X implies that each O  is a union of certain  B ’s and the
                 i                                       j                   i
                          C
          totality of all such  B ’s that arise in this way is a basic open cover of X. By De-Morgan’s law, the
                          i
          totality of corresponding B ’s has empty intersection and therefore by the given hupothesis this
                                i
          totality does not have FIP. This implies that there exist finitely many B ’s, say,
                                                                   i
                                     n
                  B ,B  B  n i  such that   B   .
                   1 i  2 i             K i
                                    K 1
                                     
          Taking complements on both sides, we set
                  n
                     C
                    B   X.  (By De-Morgan’s Law)
                     K i
                   
                  K 1
                   C
                                                         C
          For each  B  (K = 1, 2, …, n) we can find a  O such that  B   O .
                   K i                        K j        K i  K j
                   n
          Thus X =   O .
                      K j
                   
                  K 1
          Thus, we have shown that every basic open cover of X has a finite sub-cover.
                 Example 2: Let X be a non-empty set. Then every class {B} of subsets of X with the FIP is
                                                              j
          contained in some maximal class with the FIP.
          Solution: Let {B} be a class of subsets of X with the FIP and let P be the family of all classes of
                      j
          subsets of X that contains {B} and have the FIP.
                                 j
          For any F , F   P, define F   F  so that F   F .
                                          
          Then (P,  ) is a partially ordered set. Let  be any totally ordered subset of (P, ). Then, the union
          of all classes in  has an upper bound for  in P.
          Thus (P, ) is a partially ordered set in which every totally ordered subset has an upper bound.
          Hence by Zern’s lemma, P possesses a maximal element i.e., there exist a class {B } of subsets of
                                                                           K
          X such that {B}  {B }, {B } has the FIP and any class of subsets of X which properly contains {B }
                     j    K   K                                                      K
          does not have the FIP.
          Tychonoff’s Theorem

          Before proving Tychonoff’s theorem, we shall prove two important lemmas.
          Lemma 1: Let X be a set; Let  be a collection of subsets of X having the finite intersection
          property. Then there is a collection D of subsets of X such that D contains  and D has the finite
          intersection property, and no collection of subsets of X that properly contains D has this property.

          We often say  that a collection D satisfying the  conclusion of this theorem is maximal with
          respect to the finite intersection property.





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