Page 86 - DMTH503_TOPOLOGY
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Topology




                    Notes
                                          Example 2: Let (X , T ), …, (X , T ), … be a countably infinite family of topological spaces.
                                                       1  1     n  n
                                   Then the box topology T on the product  Õ ¥ i 1 X  is that topology having as its basis the family
                                                                         i
                                                                      =
                                                     B = { Õ  O : O Î T i }
                                                          ¥
                                                                i
                                                             i
                                                          =
                                                         i 1
                                   It is readily seen that if each (X , T ) is a discrete space, then the box product  (Õ ¥ i 1 X , T ) is a
                                                            i  i                                     =  i
                                   discrete space. So if each (X , T) is a finite set with the discrete topology, then  (Õ ¥ i 1 X , T ) is an
                                                         i                                          =  i
                                   infinite discrete space, which is certainly not compact. So, we have a box product of the compact
                                   spaces (X , T ) being a non-compact space.
                                          i  i
                                          Example 3: Let (X , T ), …, (Y , T), iÎN, be countably infinite families of topological
                                                        i  i     i  i
                                   spaces having product spaces (Õ ¥ i 1 X ,  ) T  and (Õ ¥ i 1 Y , T )  respectively. If the mapping h : (X , T )
                                                             =
                                                                          =
                                                                i
                                                                             i
                                                                                                         i
                                                                                                            i
                                                                                                              i
                                    (Y , T ) is continuous for each i Î N, then so is the mapping h: (Õ ¥ i 1 X ,  ) T   (Õ ¥ i 1 Y , T )  given
                                       i  i                                            =  i        =  i
                                   by h : (Õ ¥ i 1 x i  ) = Õ ¥ i 1 h (x ); that is, h (x , x , …, x , …) = h (x ), h (x ), …, h (x ), ….
                                          =
                                                       i
                                                     i
                                                  =
                                                                      2
                                                                                          2
                                                                                                  n
                                                                                                n
                                                                                     1
                                                                   1
                                                                                   1
                                                                                        2
                                                                           n
                                                                                                   –1
                                   Solution: It suffices to show that if O is a basic open set in  (Õ ¥ i 1 Y , T ) , then h (O) is open in
                                                                                     =
                                                                                        i
                                     ¥
                                   (Õ i 1 X ,  ) T .  Consider the basic open set   ×   × …   × Y  × Y  × … where   Î T, for i = 1,
                                         i
                                      =
                                                                                  n+1
                                                                              n
                                                                                                   i
                                                                                       n+2
                                                                     1
                                                                        2
                                   …, n. Then
                                         h  (  × … ×    × Y  × Y  × …)
                                          –1
                                              1      n   n+1  n+2
                                                                      –1
                                                      –1
                                          –1
                                        = h  ( ) × … × h  (  )× h  (Y ) × h  (X ) × …
                                                             –1
                                          1   1       n  n       n+1     n+2
                                                                                                    –1
                                   and the set on the right hand side is in T, since the continuity of each h  implies h  ( ) Î T , for
                                                                                           i        1  i   i
                                   i = 1, …, n. So h is continuous.
                                   8.1.3 Cartesian Product
                                   Definition: Let {A }  be an indexed family of sets; let X =    A . The cartesian product of this
                                                  ÎJ                             ÎJ  
                                   index family, denoted by  Õ  A , is defined to be the set of all J-tuples (x )  of elements of X such
                                                           
                                                                                            ÎJ
                                                       Î J
                                   that x  Î A  for each  Î J. That is, it is the set of all functions
                                          
                                                                   x : J    A 
                                                                         Î J
                                   such that x() Î A  for each  Î J.
                                                 
                                   8.1.4 Box Topology
                                   Let {X }   be an indexed  family of topological spaces. Let us take as a basis for a topology on the
                                         Î J
                                   product space Õ  X the collection of all sets of the for Õ    , where    is open in X , for each  Î J.
                                                 
                                              Î J                          Î J                 
                                   The topology generated by this basis is called the box topology.
                                          Example 4: Consider euclidean n-space  . A basis for  consists of all open intervals in
                                                                          n
                                                                 n
                                   ; hence a basis for the topology of   consists of all products of the form
                                                             (a , b ) × (a , b ) × … × (a , b )
                                                               1  1   2  2       n  n
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