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Differential and Integral Equation




                    Notes                         2
                                   (ii)  (n) = 2  e  x  x 2n  1
                                               0
                                   (iii)  (1) = 1

                                   (iv)  (1/2) =
                                   (v)  (n + 1) = n  (n),      n > 0
                                   (vi)  (n + 1) = 1. 2. 3. ...n = n!  for n a +ve integer


                                   (vii)  (n)  (1   n) =
                                                    sinn
                                   (viii)  (m) =   if m = 0 or   ve integer

                                              2 2n  1
                                   (ix)  (2n) =     ( )  n  1/2
                                                    x

                                   1.3 On Second Order Differential Equation of the Fuchs Type
                                               ,
                                   Consider Bessel s equation for any n:

                                                          2
                                                        2 d y  dy   2  2
                                                       x     x    (x  n  )y = 0
                                                         dx 2  dx
                                                         2
                                                        d y  1 dy     n 2
                                   Or                     2        1   2  y = 0                            ...(A)
                                                        dx   x dx     x
                                                                              1
                                   Let                                 p(x) =
                                                                              x
                                                                                                           ...(B)
                                                                                 n 2
                                                                       q(x) = 1
                                                                                 x  2
                                   Thus p(x) has a pole at x = 0 and q(x) has a double pole at x = 0. Thus x = 0 is a singular point of
                                       ,
                                   Bessel s Differential Equation. Since
                                                     2
                                            x p(x) and x  q(x),                                            ...(C)
                                   are finite at x = 0, the point x = 0 is a regular singular point of Bessel Differential equation. Also
                                   by putting x = 1/r as independent variable we can show that x =   is an irregular singular point.
                                   To see this put
                                                 1      1
                                              x =  ,  r =
                                                 r      x

                                             dy   dy dr  dy  1     2 dy
                                   Then         =            2    r
                                             dx   dr dx  dr x       dr

                                             2
                                            d y   =  d  r 2 dy
                                            dx 2  dx    dr






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