Page 217 - DMTH504_DIFFERENTIAL_AND_INTEGRAL_EQUATION
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Differential and Integral Equation




                    Notes          Putting   =  x,
                                                          d
                                                       x     J n ( x ) n J n ( x ) =  x J  ( x )
                                                          ( d x )                 n  1

                                   or                       x J  1 ( x ) n J  ( x ) =  x J  ( x )
                                                              n       n           n  1
                                   Substituting in (v), we have

                                                                                                    a
                                                                        2  a                  a
                                                                                       2
                                                      n J  ( x )  x J  ( x )  =   2 2  n J  2 ( x )  2  2  x J  2  ( x )dx
                                                                                   x
                                                         n        n  1                   n              n
                                                                         0                    0
                                                                                                    0
                                                J
                                   If    mn  ,  then  n ( a )  J n  mn a  0,  and
                                        J  (0) 0,  for n = 1, 2, ...,
                                   Since  n
                                   then we have
                                                                                   a
                                                             2  2  2          2  2  x J 2  x dx
                                                             mn  a J  n  1  mn  a  =  mn  n  mx
                                                                                   0

                                                                           = 2   2 mn  J n (  mn  ) x  2  {since weight = x}
                                   Thus


                                                                         2    a 2  2
                                                                  J n (  mn  ) x  =  J n  1  (  mn  ) a
                                                                               2
                                                                              a 2  2
                                                                           =    J  n  1  (  mn )
                                                                               2
                                   where                                   =     a
                                                                        mn     mn
                                                                                        a
                                                                                  2
                                                                                                 f
                                                                                                   x
                                   So                                   C  =   2  2      x J n (  mn  x ) ( )dx  ...(vi)
                                                                          n   a J  (   )
                                                                                  1
                                                                                     mn
                                                                                 n
                                                                                        0
                                   and                                     =    mn  ,  for m = 1, 2, 3....
                                                                        mn     a
                                   Thus generalized Fourier Bessel series is given by (iii) with the coefficient C  given by (vi).
                                                                                                n
                                   (b) Orthogonality of Legendre Polynomials
                                   The Legendre’s differential equation

                                                     (1 x 2 )y  2xy  ( n n  1)y  = 0

                                   may be written as

                                                             [(1 x 2 ) ]  y = 0                            ...(i)
                                                                    y
                                                                                               where  = n (n + 1),




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