Page 353 - DMTH504_DIFFERENTIAL_AND_INTEGRAL_EQUATION
P. 353

Differential and Integral Equation




                    Notes          Elliptic Equations: ac > b 2

                                   In this case we can make neither A nor C zero, since no real characteristic curves exist. Instead we
                                   can simplify by making A = C and B = 0, so that the second derivative form the Laplacian   2   and
                                   the canonical form is
                                             +    + b ( ,  )  + b ( ,  )   + b   = g( ,  )                ...(14)
                                                   1         2        3
                                   Clearly Laplace s equation is in canonical form
                                   In order to proceed, we must solve

                                                           b
                                          A   C =  (a  2 x   2 y ) 2 (      ) c (  2 y   2 y ) 0
                                                                   x y
                                                             x y
                                          B =  a   ( b       ) c   0.
                                               x x
                                                                 y y
                                                      x y
                                                           x y
                                   We can do this by defining x =  + i , and noting that these two equations form the real and
                                   imaginary parts of
                                            2           2
                                          a x  2b   c x  0
                                                 x y
                                   and hence
                                           x  b   ac  b 2
                                           y      a                                                      ...(15)

                                   Now   is constant on curves given by  dy +  dx = 0, and hence from (15) on
                                                                  y     x
                                          dy  b   ac  b 2
                                                                                                          ...(16)
                                          dx      a
                                   By solving (16) we can deduce  ,  . For example consider elliptic equation
                                                 4
                                             + sech x    = 0                                              ...(17)
                                           xx       yy
                                   In this case   =   + i  is constant on the curves given by
                                          dy        2
                                                i sech x ,
                                          dx
                                   and hence  y   i tanb x = constant. We can therefore take   = y + i tanb x, and hence   = y,   = tanb
                                   x. On writing (17) in terms of these variables, with  (x, y) =  ( ,  ), we find that the canonical
                                   form is
                                                     2n
                                                      ,                                           ...(18)
                                                   (1  2 )
                                   in the domain | | < 1.

                                   21.3 Classification of Second order Partial Differential Equations


                                   Let us consider a function  z  of two  independent variables  x and  y. Writing various partial
                                   derivatives as

                                              z     z     2 z    2 z    2 z
                                          p    , q   , r   2  , s  , t   2                                 ...(1)
                                              x     y     x     xdy     y



          346                               LOVELY PROFESSIONAL UNIVERSITY
   348   349   350   351   352   353   354   355   356   357   358