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Differential and Integral Equation




                    Notes          Let us take the initial i.e. undisturbed position of the string to be the axis of x and suppose that
                                   the motion is confined to the xy plane. Consider the motion of an element PQ of length as shown
                                   in the Figure 23.1.
                                   The net force in the y direction, Fy, is given by

                                        Fy  T  sin  T sin                                                   ...(i)
                                                2       1
                                   Now, for small oscillations, we may write

                                                      y
                                        sin  2  tan  2                                                     ...(ii)
                                                      x
                                                        x dx
                                                      y
                                        sin  1  tan  1                                                    ...(iii)
                                                      x  x
                                                                    Figure  23.1


                                                    Y                                T
                                                                               Q       2



                                                                 1
                                                                  P
                                                       T





                                                  0
                                                                                         X
                                   Therefore, we have

                                               y        y
                                        F y  T       T                                                     ...(iv)
                                               x  x dx  x  x
                                                                                  2
                                   Using Taylor s expansion and neglecting terms of order dx and higher, we have
                                               y         y        y
                                        F y  T        T     dx  T
                                               x    x    x        x
                                                 x         x        x
                                                 y
                                   or   F y   T     dx                                                     ...(v)
                                            x    x
                                                   x
                                   By Newton s Law of motion, we have
                                                 y          2 y
                                        F     T    dx  mdx
                                         y                   2                                             ...(vi)
                                            x    x          x
                                   where mdx represents the mass of the section of string under consideration and where we have
                                                                         2
                                                                          y
                                   written dx for ds since the placement is small   2   is the acceleration of the section of string in
                                                                         x
                                   the y direction, we thus have



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