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Unit 23: Wave and Diffusion Equations by Separation of Variable




          This leads to the equation                                                            Notes
                          s
               0  AJ  0  2                                                        ...(15)
                          g

          Now, for a non-trivial solution, A cannot be equal to zero, and hence we have

                      s
               J  2       0
                0                                                                 ...(16)
                      g
          If we let

                      s
               u  2
                      g                                                           ...(17)
          we must find the roots of the equation
               J u   0                                                            ...(18)
                0
          If we consult a table of Bessel functions, we find that the first three zeros of the Bessel function
           J u are given by the values
           0
               2.405, 5.52, 8.654
          Accordingly the various possible values of   are given by
                   2.405 g          5.52  g        8.654  g
                 1               2              3         etc.                    ...(19)
                     2   s           2   s          2   s
          To each value of   we associate a characteristic function or eigenfunction v  of the form
                                                                      n
                            x
               v n  A J  0  2  n                                                  ...(20)
                    n
                            g
          Since the real and imaginary parts of  the assumed  solution (7) are solutions of the  original
          differential equation, we can construct a general solution of (6) satisfying the boundary conditions
          by summing the particular solutions corresponding to the various possible values of  n in the
          manner
                      n        x
               y  , x t  J  2     A  cos  t B  sin  t
                         0   n      n    n   n    n                               ...(21)
                      n  1      g
          where the  quantities  A and B  are arbitrary constants to be determined from the boundary
                             n     n
          conditions of the problem. In the case under consideration there is no initial velocity imparted
          to the chain; hence
                 y
                       0                                                          ...(22)
                 t  t  0
          This leads to the condition

               B n  0                                                             ...(23)
          At t = 0 we have

                     n           x
               y x      A J  2
                0        n  0  n  g                                               ...(24)
                     n  1



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