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Unit 14: Radon-Nikodym Theorem




                                                                                                Notes

             Notes

                If   is  -finite, the converse is also true.
                If   and   are signed measures on (X, ), then        if | |    | |.

          Radon-Nikodym Theorem

          Let (X, ,  ) be a  -finite measure space. If  be a measure  defined on  A s.t.  is  absolutely
          continuous w.r.t.  , then there exists a non-negative measurable function f on s.t.


                                    (A) =   f d , A  .
                                          A
          The function f is unique in the sense that if g is any measurable function with the property
          defined as above, then f = g almost everywhere with respect to  .
          Proof: To establish the existence of the function f, we shall use the following two Lemmas:
          Lemma 1: Let E be a countable set of real numbers. Let for each a   E there is a set F     s.t.
                                                                               a
          F    F , whenever b < a i.e. <F > is a monotonic decreasing sequence of subsets of  corresponding
           a   b                 n
          to the sequence <a > of real numbers in E. Then   a measurable extended real valued function f
                         n
          on X s.t.
                 f (x)   a, x   F ,
                             a
          and    f (x)   a, x   (X – F ).
                                a
          Proof: Let f (x) = inf {a : x   F } x   X and let, conventionally
                                  a
                         inf {empty collection of real numbers} =
          Now,   x   F     f(x)   a
                      a
                 x   F     x   F  for every b < a
                      a      a
                           f (x)   a
          Now,   f (x) < a    x   F  for some b < a
                              b
                             
          or     {x : f (x) < a} =   [F ]
                                 b .
                             b a
          Also x   F     f (x)   b < a for some b < a.
                  b
          Hence f is measurable.
          Again, by definition of f, we observe that

                 f (x)   a, x   F ,
                             a
          and    f (x)   a, x   F .
                             a
          Thus f is the required function.
          Lemma 2: Let E be a countable set of real numbers. Let corresponding to each a   E, there is a set
          F     s.t.
           a
                   (F  – F ) = 0 whenever b > a.
                    a   b
          Then there exists a measurable function f with the property
                 x   F     f (x)   a a.e.
                     a
          and    x   (X – F )    f (x) > a a.e.
                         a


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