Page 177 - DMTH505_MEASURE_THEOREY_AND_FUNCTIONAL_ANALYSIS
P. 177

Measure Theory and Functional Analysis




                    Notes          For each n   N, define
                                                              1
                                          A  =  x X : f(x) g(x)  
                                                              n
                                           n
                                                             1
                                   and    B  =  x X :g(x) f(x)    .
                                           n                 n

                                                   1
                                   Since f (x) – g (x)     ,  x A n , we have by first mean value theorem
                                                   n
                                                     1
                                            (f g)d     (A )
                                                         n
                                                     n
                                          A n
                                                       1
                                            fd    gd      (A )
                                                            n
                                                       n
                                          A n   A n
                                                      1           1
                                           (A ) –  (A )     (A ) or 0  (A )
                                             n    n   n   n       n    n
                                            (A )   0.
                                             n
                                   Since  (A ) is always greater than equal to zero, we have  (A ) = 0.
                                           n                                        n
                                   Similarly, we can show that
                                                            (B )   0.
                                                             n
                                   If                        C = {x   X : f (x)   g (x)}

                                                               =   (A   B ),
                                                                         n
                                                                      n
                                                                  n 1
                                   then     (C) = 0   f = g a.e. on X w.r.t.  .
                                   Hence the theorem.
                                   Theorem 1: If  ,   are  -finite signed measures on (X, A) and       ,    , then
                                              1  2                                   1     2
                                                          d(    )  d   d      d    d(  )
                                                            1   2    1   2  and  1     1
                                                            d      d    d     d     d
                                   Proof: Since  ,   are  -finite and      ,      , we have that   +   is also  -finite and
                                              1  2              1      2                  1   2
                                     +      .
                                   1   2
                                   Now for any A   ,
                                                      (  +  ) (A) =   (A) +   (A)
                                                       1  2       1     2

                                                                   d       d       d    d
                                                               =     1 d    2 d      1    2  d
                                                                   d       d        d   d
                                                                 A       A       A
                                            d            d    d
                                              1   2  d     1    2  d
                                              d           d   d
                                          A            A




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