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Measure Theory and Functional Analysis




                    Notes                                      =   x + y     x   +   x + y      y
                                                               = (  x   +   y  ) (  x + y  ).
                                   If   x + y   = 0, then the above inequality is evidently true.
                                   If   x + y     0, we can divide both sides by it to obtain

                                                          x + y      x   +   y  .

                                                                          1             1
                                                                   n       2      n      2
                                   (iii)                     x  =   | x | 2  | |   |x | 2
                                                                        i            i
                                                                   i 1           i 1
                                                               = | |  x  .
                                   This proves that R  or C  are normed linear spaces.
                                                 n
                                                      n
                                                                 n
                                   Now we show the completeness of C  (or R ).
                                                                      n
                                                                            n
                                   Let < x , x , … x  > be a Cauchy sequence in C  (or R ). Since each x  is an n-tuple of complex (or
                                                                       n
                                        1  2   n                                        m
                                   real) numbers, we shall write
                                                             x =  x (m) , x (m) , , x (m)
                                                              m    1   2       n
                                                   th
                                   So that  x (m)   is the k  coordinate of x .
                                          k                     m
                                   Let   > 0 be given, since <x > is a Cauchy sequence, there exists a positive integer m , such that
                                                        m                                             o
                                                        , m   m    x  x
                                                              o     m   
                                                                         2
                                                                   x   x    2
                                                                    m   
                                                                   n
                                                                     x (m)  x  ( )   2                    … (1)
                                                                      i    i
                                                                  i 1

                                                                   x (m)  x ( )   2   (i = 1, 2, ……, n)
                                                                        i
                                                                   i
                                                                   x (m)  x ( ) 
                                                                   i    i

                                   Hence  x (m)  m 1    is  a  Cauchy  sequence  of  complex  (or  real)  numbers  for  each  fixed  but
                                           i
                                   arbitrary i.
                                   Since C (or R) is complete, each of these sequences converges to a point, say 2  in C (or R) so that
                                                                                                i
                                                        Lim x (m)  = z  (i = 1, 2, …, n)                   … (2)
                                                        m   i     i
                                                                                                            n
                                   Now we show that the Cauchy sequence <x > converges to the point z = (z , z , ……, z )   C  (or
                                                                     m                        1  2     n
                                   R ).
                                    n
                                   To prove this let       in (1). Then by (2) we have
                                                                   n
                                                                           2
                                                                     x (m)  z  2
                                                                      i   i
                                                                  i 1




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