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Unit 2: Functions of Bounded Variation




          Again, if x<y in [a,b], then as above                                                 Notes
                     y
          v y   v x  V f  f y  f x  f y  f x
                     x

            v y  f y  v x  f x    v f y  v f x

            v f is also a non-decreasing function on [a,b].

          Thus (i) shows that f is expressible as a difference of two monotonically non-decreasing functions.
          Case II. Set g (x) and h (x) be increasing functions such that f(x) = g(x) – h(x).
          Divide the closed interval [a,b] by means of points

          a = x < x < x <...< x =b.
              0   1  2    n
                 n 1
          Let  V   f x   f x
                     r 1    r
                 r 0
          Now, we have that
           f x   f x   g x    h x    g x   h x
             r 1    r     r 1    r 1    r     r
                                   g x  g x  h x  h x
                           r 1   r       r    r 1
                                   g x r 1  g x r  h x r  h x r 1
                                   g x  g x  h x  h x
                          r 1   r      r 1    r
          Now,  g(x)  and  h(x)  are  monotonically  increasing  functions,  so  that  g x r 1  g x r  0

          and h x    h x   0
                 r 1    r
             g x    g x   g x   g x
                r 1   r      r 1   r

          and  h x r 1  h x r  h x r 1  h x .
                                     r
          Hence  f x  r 1  f x  r  g x r 1  g x  r  h x r 1  h x r

            n 1            n 1              n 1
               f x   f x      g x    g x       h x    h x
                 r 1    r        r 1    r         r 1    r
            r 0            r 0              r 0
               n 1
          Now     g x r 1  g x r  g x 1  g x 0  g x 2  g x 1  ..... ....  g x n  g x n 1
               r 0

            g x n  g x  0
            g b  g a             x  b,x  a
                            n     0
                   n 1
          Similarly,   h x   h x    h b  h a .
                         r 1    r
                   r 0
                n 1
          Hence    f x  r 1  f x  r  g b  g a  h b  h a .
                r 0



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