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Unit 4: Absolute Continuity




                                                                                                Notes
          where  f x n  and  f x n  are the maximum and maximum values of f(x) in the interval [a ,b ].
                                                                                 n
                                                                                   n
          Also note that   n x  x n  b n  a n


            m * f E   , being arbitrary.

            m * f E  0   m f E   0.



                 Example: Give an example which is continuous but not absolutely continuous.

          Solution: Consider the function  f : F  R, where F is the Cantor’s ternary set.

                                 x
          Let  x F  x  x x x ...  k  ,x  0 or 2
                       1  2  3   3 k  k
                               K 1
                        r           1
          Define  f x    k  , where r  x .
                        2  k      k  2  k
                      K 1
                               = 0. r , r , r .....
                        1  2  3
          This function is continuous but not absolutely continuous.
          (i)  Note that this function is constant on each interval contained in the complement of the
               Cantor’s ternary set.

                                                                        c
               For, let (a,b) be  one of the countable open intervals  contained in  F . Then in ternary
               notation,
               a = 0.a a ...a  0 2 2 2
                    1 2  n–1
               and b = 0.a a ...a 2 0 0 0,
                        1 2  n-1
               where a = 0 or 2, for  i  n 1.
                     i

                                                  a
                 f a  0.r ,r ,...,r  0 1 1 1 1 ...,where r i  i  ,
                        1
                              n 1
                          2
                                                   2
               f b  0.r ,r ,...,r   1 0 0 0 0 ...
                      1  2  n 1
               But in binary notation
               0.r ,r ,...,r  0 1 1 1 1 ... 0.r ,r ,...,r  1 0 0 0 0 ...
                                       2
                                           n 1
                                     1
                   2
                       n 1
                 1
                 f a  f b .
               Thus,  we  extend  the  function  f  overall  of  the  set  [0,1]  instead  of  F  by  defining
                                   c
               f x  f b , x  a,b  F .  Thus, the Cantor’s function is defined over [0,1] and maps it
               onto [0,1].
               It is clearly a non-decreasing function.






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