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Methodology of Social Research




                     notes
                                            Example 7    Use the following table to compute the standard deviation


                                                         Weight (in Pounds)       Number of People
                                                               70–80                    12

                                                               80–90                    18
                                                               90–100                   35
                                                              100–110                   49
                                                              110–120                   50

                                                              120–130                   45
                                                              130–140                   20
                                                              140–150                    8

                                      to solve this question using short-cut method, we will assume the centre–value of any of the class
                                      intervals to be the mean.
                                                  +
                                      Let us say  110 120  = 115  is the mean. Now we form the following table.
                                                  2

                                        Weight (in   number of    Mid–      Variation   Variation of   f × d =   fd × d =
                                         pounds)      People     point of   of Mid–     (d) Mid–     fd        fd 2
                                           C.I.         (f)       Class–   point from   point from
                                                                 intervals  assumed     assumed
                                                                    x        Mean      Mean 115
                                                                             (X – A)   divided by
                                                                                       class width
                                                                                        (X–A/i)
                                          70–80         12          75        –40         –4         –48       192
                                          80–90         18          85        –30         –3         –54       162

                                          90–100        35          95        –20         –2         –70       140
                                         100–110        49         105        –10         –1         –49       49
                                         110 –120       50         115         0           0          0        0
                                         120–130        45         125         10          1         45        45
                                         130 –140       20         135         20          2         40        80

                                         140–150        8          145         30          3         24        72
                                                N = 237                                          S fd = –112  Sfd  = 740
                                                                                                              2

                                      formula—
                                                                                                    
                                                                                 S  fd 2    S  fd  2  740 − 112  2
                                                                         σ  =  i  N  −      N     =  10  237     237   





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