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Unit 8: Correlation Analysis




                                                                                                Notes
          sum of positive products and hence   X i  X Y i  Y   will be negative for all the n observations.

          Further, if there is no correlation, the sum of positive products of deviations will be equal to the
          sum of negative products of deviations such that   X i  X Y i  Y  will be equal to zero.


          On  the basis of the  above, we  can consider   X  i  X Y i  Y   as an  absolute measure  of
          correlation. This measure, like other absolute measures of dispersion, skewness, etc., will depend
          upon (i) the number of observations and (ii) the units of measurements of the variables.
          In order  to avoid  its dependence on the number of observations, we  take its  average,  i.e.,
           1
               X i  X Y i  Y . This term is called covariance in statistics and is denoted as Cov(X,Y).
           n
          To eliminate the effect of units of measurement of the variables, the covariance term is divided
          by the product of the standard deviation of X and the standard deviation of  Y. The resulting
          expression is known as the Karl Pearson's coefficient of linear correlation or the product moment
          correlation coefficient or simply the coefficient of correlation, between X and Y.

                             Cov X  ,Y
                         r XY                                       .... (1)
                                X Y
                           1
                               X i  X Y i  Y
                           n
          or      r XY  1         2 1         2                     .... (2)
                            X i  X       Y i  Y
                        n           n
                    1
          Cancelling    from the numerator and the denominator, we get
                    n
                                     X  i  X Y i  Y
                         r XY           2         2                 .... (3)
                                  X i  X     Y i  Y


          Consider    X i  X Y i  Y    X i  X Y i  Y  X i  X

                                            X Y  X   Y i (second term is zero)
                                             i i

                                            X Y  nX Y   Y i  nY
                                             i i
                                       2      2    2
          Similarly we can write   X  i  X  X  i  nX
                                             2     2    2
                         and                Y i  Y  Y i  nY
          Substituting these values in equation (3), we have

                                        X Y  nXY
                                         i i
                         r XY
                                  X 2  nX  2   Y  2  nY  2          .... (4)
                                    i           i







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