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Quantitative Techniques – I




                    Notes          Since the Spearman's formula is  based upon  the assumption of different  ranks to different
                                   individuals, therefore, its correction becomes necessary in case of tied ranks. It should be noted
                                   that the means of the ranks will remain unaffected. Further, the changes in the variances are
                                                                                                 2
                                   usually small and are neglected. However, it is necessary to correct the term Sd  and accordingly
                                                                                                 i
                                                       2
                                                   m m   1
                                   the correction factor   , where m denotes the number of observations tied to a particular
                                                      12
                                                                                                         2 4 1
                                   rank, is added to it for every tie. We note that there will be two correction factors, i.e.,
                                                                                                           12
                                       3 9 1
                                   and        in the above example.
                                        12

                                   8.2.2 Limits of Rank Correlation

                                   A positive rank correlation implies that a high (low) rank of an individual according to one
                                   characteristic is accompanied by its high (low) rank according to the other. Similarly, a negative
                                   rank correlation implies that a high (low) rank of an individual according to one characteristic
                                   is accompanied by its low (high) rank according to the other. When    = +1, there is said to be
                                   perfect consistency in the assignment of ranks, i.e., every individual is assigned the same rank
                                                                                 2
                                   with regard to both the characteristics. Thus, we have  d = 0 and hence,  = 1.
                                                                                i
                                   Similarly, when  = –1, an individual that has been assigned 1st rank according to one characteristic
                                   must be assigned nth rank according to the other and an individual that has been assigned 2nd
                                   rank according to one characteristic must be assigned (n – 1)th rank according to the other, etc.
                                   Thus, the sum of ranks, assigned to every individual, is equal to (n + 1), i.e., X  + Y  = n + 1 or
                                                                                                  i   i
                                   Y  = (n + 1) – X ,  for all i = 1, 2, ...... n.
                                    i         i
                                   Further,   d  = X  – Y  = X  – (n + 1) + X  = 2X  – (n + 1)
                                            i  i  i   i         i    i
                                   Squaring both sides, we have

                                                             d  2  2X  n  1  2  4X  2  n  1  2  4 n  1 X
                                                              i     i            i                i
                                   Taking sum over all the observations, we have
                                                                                                        2
                                                            2               4n n  1 2n  1      2  4n n  1
                                              d i 2  4 X i 2  n n  1  4 n  1  X i  6      n n  1     2

                                                                                                  2
                                                           2                       n n  1 n  1  n n  1
                                                     n n  1  2n  1  n  1  2 n  1
                                                           3                           3          3
                                   Substituting this value in the formula for rank correlation we have
                                                          2
                                                       6n n  1     1
                                                    1                     1
                                                          3     n n 2  1
                                   Hence, the Spearman's coefficient of correlation lies between - 1 and + 1.


                                          Example: The following table gives the marks obtained by 10 students in commerce and
                                   statistics. Calculate the rank correlation.
                                            Marks in Statistics  : 35 90 70 40 95 45 60 85 80 50
                                            Marks in Commerce : 45 70 65 30 90 40 50 75 85 60




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