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Operations Research




                    Notes              (ii)  Modified Matrix – 2
                                                To   A            B           C            D           E
                                    From
                                         a            -           0            1           0           0
                                         b            0           -            0           0           1
                                         c            2           2            -           6           0
                                         d            0           0            2           -           3
                                         e            2           0            0           6            -

                                       Note: This alternative cannot be worked out as no unique zero remains in the third row
                                       after choosing next minimum  element '1' in the II row.
                                  (3)  Calculation of Travelling Expenses.

                                              From                     To                Travelling Expenses (`)
                                               a                        3                       12
                                               b                        4                        5
                                               c                        5                        3
                                               d                        1                        5
                                               e                        2                        2
                                                                         Total Expenses         27

                                  Inference
                                  The minimum travelling expenses with an unique and optimum solution to the above problem
                                  works to be ` 27.

                                  (4)  Modified Matrix-1.
                                                To   A            B           C            D           E
                                    From
                                         a                       0           2            0           1
                                         b            0                      0            0           1
                                         c            1           0                       2           0
                                         d            0           0           3                       5
                                         e            0           0           0            4           

                                  Note: There are three alternative solutions to the above matrix.
                                  (5)  (a)  Alternative  1               (b) Alternative - 2              (c) Alternative - 3
                                        From         To          From         To          From         To
                                         a            B           a           D            a           D
                                         b           D            b           A            b           C
                                         c            E           c            E           c            E
                                         d           A            d            B           d           A
                                         e           C            e           C            e            B

                                       Note: Observe there is presence of looping in all the three solutions. Hence, they are not
                                       the unique solutions to travelling salesman problem. Further, the matrix is to be modified.




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