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Unit 8: Assignment Problem – Unbalanced




                                                                                                Notes
                Example: Solve the following travelling salesman problem with the following matrix.

                                        Travelling Expenses
                  To
            From                  1          2           3          4          5
                       I          -          6           12         6          4
                      II          6          -           10         5          4
                      III         8          7           -          11         3
                      IV          5          4           11         -          5
                      V           5          2           7          8          -

          Solution:


          Apply Reduction Theorem Rules
          1.   Row-wise Reduced Matrix.

                  To
           From                  1           2           3          4          5
                      I          -           2           8          2          0
                      II         2           -           6          1          0
                      III        5           4           -          8          0
                     IV          1           0           7          -          1
                      V          3           0           5          6          -
          2.   Column-wise Reduced Matrix.

                   To
            From                  1          2          3          4           5
                       I          -          2          3          1           0
                       II         1          -          1          0           0
                       III        4          4          -          7           0
                       IV         0          0          2          -           1
                       V          2          0          0          5           -
                                                                                                                                                                                      L1                                  L2
          Note: Used Hungarian approach and get the improvised matrices.

          3.   Modified Matrix  – 1.

                   To
           From                    1          2          3          4          5
                        I          -          1          2          1          0
                       II          0          -          0          0          0
                       III         3          3          -          7          0
                       IV          0          0          2          -          0
                       V           2          0          0          6          0
                                                                                                                                                                        L1                      L2






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