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Unit 6: Functions




                                                                                                Notes
                                               8000 5000
          Thus,               we have C - 5000 =           x  200   15(x   200)
                                                400 200
          or                               C = 15x + 2000, is the required cost function.
          Further, the fixed cost is   2,000.


                 Example
          The demand and supply of a commodity are given by x  = 81000 – 160p and x  = –4500 + 125p,
                                                       d                 s
          where x denotes quantity and p denotes price. Find the equilibrium price and quantity.
          Solution:
          We know that  x  x  in equilibrium
                        d   s
                   81000 – 160p = –4500 + 125p


          Thus,           285p = 85500 or   –   t   =   300


          Also equilibrium quantity x = 81000 - 160 × 300 = 33000 units.

                 Example

          When price of a  commodity is   30 per unit, its demand  and supply are 600  and 900  units
          respectively. A price of   20 per unit changes the demand and supply to 1000 and 700 units
          respectively. Assuming that the demand and supply equations are linear, find
          (i)  The demand equation
          (ii)  The supply equation
          (iii)  The equilibrium price and quantity

          Solution:
          Note: In both the situations of demand or supply, the price is an independent variable and the quantity a
          dependent variable. However, while plotting them, price is taken on vertical axis and quantity on the
          horizontal axis. This is an exception to the convention followed in most of the other topics of
          economics as well as in other branches of science, where the independent variable is taken along
          horizontal axis and the dependent variable along vertical axis.
          (i)  The demand equation is the equation of line passing through  the points  (600, 30) and
               (1000, 20). Thus, we can write
                                       30 20
                              p – 30 =         (x d  – 600)
                                     600 1000
               On simplification, we get the demand equation as x  = 1800 – 40p.
                                                        d
          (ii)  The supply equation is the equation of a line passing through the points (900, 30) and
               (700, 20). Thus, we can write

                                      30 20
                              p – 30 =        (x s  – 900)
                                     900 700

               On simplification, we get the supply equation as x  = 300 + 20p.
                                                       s


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