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Unit 12: Successive Differentiation




          5.   Let  y  xe  x                                                                    Notes
                    dy    x  x
                        xe  e  1
                    dx

                     2
                    d y        x   x
                         x  1 e   e  1
                    dx 2
                       x  2 e x

                  d  3 y
                       (x   ) 2 e  x  e  x  1 .
                  dx 3
                      x (  e ) 3  x

                  d  4 y     x   x
                       (x   ) 3 e  e  1 .
                  dx  4
                       x (  e ) 4  x

                                                   2
                                                  d y
                 Example: If  x 2  xy y  2  0,  prove that   0 .
                                                  dx 2
          Solution:  x 2  xy y  2  0

                 Differentiating w.r.t. x, we get
                       dy        dy
                  2x x     y  2y     0
                       dx        dx
                  dy
                     x  2y     2x y
                  dx

                      dy    2x y
                      dx    x  2y

                                       dy               dy
                             x  2y  2        2x y   1 2
                       2
                      d y              dx               dx
                      dx 2               x  2y  2


                           2x y                (2x y )
                      y
                 (x  2 ) 2          (2x y  ) 1 2
                           x  2y               (x  2 )
                                                   y
                                     y
                                (x  2 ) 2
                   x  2y  3y  2x y   3x
                                3
                          x  2y

                   3xy  6y  2  6x  2  3xy
                               3
                         x  2y







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