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Basic Mathematics – I




                    Notes
                                                                                             3
                                          Example: Find relative maxima and minima of the function y = x  – 4x  – 3x + 2.
                                                                                                 2
                                   Also find absolute maxima/minima in [0, 4].
                                   Solution:
                                                                        2
                                                                    3
                                               Given the function y = x  – 4x  – 3x + 2, we have
                                                             dy
                                                                = 3x  – 8x – 3 = 0, for maxima or minima.
                                                                    2
                                                             dx
                                                          2
                                   Rewriting this equation as 3x  – 9x + x – 3 = 0
                                   or             3x(x – 3) + (x – 3) = 0 or (x – 3)(3x + 1) = 0
                                                                           1
                                                              x = 3 or  x
                                                                           3

                                                             2
                                                            d y
                                   Further,                     = 6x – 8 = 10 > 0, when x = 3
                                                            dx 2
                                                                                   1
                                   and                          = – 10 < 0, when  x
                                                                                   3
                                                                                    1
                                   Thus, the function has a minima at x = 3 and maxima at  x  .
                                                                                    3
                                   To find maxima/minima in [0, 4], we note that there is only one stationary point  x = 3 in the
                                   given interval.

                                                                        2
                                   Let                       f(x) = x  – 4x  – 3x + 2
                                                                    2
                                                             f(0) = 2
                                                             f(3) = 27 – 36 – 9 + 2 = –16
                                                             f(4) = 64 – 64 – 12 + 12 = –10

                                       Function has absolute maxima at x = 0, and aboslute minima at x = 3

                                                                          1
                                          Example: Show that the function  y  x   has one maximum and one minimum value
                                                                          x
                                   and later is larger than the former. Draw a graph to illustrate this.
                                   Solution:
                                                          1
                                   Given          y = x     ,  we have
                                                          x

                                                 dy       1        x 2  1    2
                                                     = 1      0  or      0  x  1
                                                 dx       x 2       x 2
                                   or             x = ±1 are the stationary points.

                                                 2
                                                d y     2
                                   Further,          =  3  ,  which will be positive when
                                                dx 2   x







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