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Basic Mathematics – I




                    Notes                                     dv   dv dr    dr   dv dv
                                   t. Using chain rule, we can write      or            .
                                                              dt   dr dt    dt   dt  dr
                                           dv          dv      2
                                   Note that    5.  Also    4 r  ,  which can be determined if r is known. To find r, we note
                                           dt          dr
                                                                                                   4   3
                                   that volume becomes 15 ´ 5 = 75 cubic feet, after 15 seconds, therefore, we have   r  75  or
                                                                                                   3
                                       225  1/3
                                   r           .
                                        4

                                        dr   5     4   2/3
                                   Thus,                   = 0.058 ft/sec.
                                        dt   4     225

                                   Rule 5.

                                   Inverse function Rule
                                   If y = f(x) and x = g(y) are inverse functions which are differentiable, then we can write g[f(x)] = x.
                                   Differentiating both sides w.r.t. x we have
                                                         g¢[f(x)] × f¢(x) = 1

                                                                         1
                                   or                           g¢(y) =
                                                                        f  ( )
                                                                          x


                                                                 dx      1
                                   or                                =      .
                                                                 dy    dy
                                                                          dx


                                          Example

                                   Find the equation of a tangent at the point (2, 3) to the rectangular hyperbola xy = 6. Show that
                                   (2, 3) is middle point of the segment of tangent line intercepted between the two axes. What are
                                   its intercepts on the two axes?
                                   Solution:

                                                  6    dy     6     6
                                   We can write  y   or          =    = -1.5
                                                  x    dx    x 2    4

                                   Equation of tangent is (y – 3) = –1.5(x – 2) or y = 6 - 1.5x.
                                   The point of intersection of the tangent with y-axis is obtained by substituting x = 0 in the above
                                   equation. This point is (0, 6). Similarly (4, 0) is a point of intersection of the tangent with x-axis.

                                   Since (2, 3) is the middle point of the line joining the points (0, 6) and (4, 0), hence the result.
                                   Intercepts of the tangent on x and y axes, are 4 and 6 respectively.







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