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Basic Mathematics – I




                    Notes                                  AVC = 100 10 5 5   2  75
                                      and                    MC = 100 20 5 3 5  2  75,  at x = 5

                                      Thus,                  MC = min. AVC
                                             2
                                                                        3
                                             d C  d MC                 d C           10
                                   (iv)  Since   =        20 6x  0  and    6 0,  at  x  ,  the total cost function has a
                                             dx 2   dx                 dx  3         3
                                       type II point of inflexion.
                                                          d MC           10
                                                     Since      = 0 at  x  ,   MC is also minimum at this value.
                                                            dx           3
                                                                          10    10 2  200
                                                    Also, min. MC = 100 20    3          66.67
                                                                           3     3 2  3


                                          Example: The cost of fuel consumed per hour in running a train is proportional to the
                                   square of its speed (in kms per hour), and it costs   3,200 per hour at a speed of 40 kms per hour.
                                   What is the most economical speed, if the fixed charges are   12,800 per hour?
                                   Solution:
                                   Let  F  be  the  cost  of  fuel  and  x  be  the  speed  of  the  train  per  hour.  We  are  given  that
                                   F   x 2   or  F  kx 2 ,  where k is a constant of proportionality.
                                                                    3200
                                   When x = 40, F is given to be 3,200,    k  2.
                                                                    1600

                                   Thus we can write  F  2x 2  , as the cost of fuel per hour of running the train when its speed is x
                                                                                                              2
                                   kms per hour. Now the total cost of running the train for x kms (per hour) is TC = 12,800 + 2x .
                                                                   12800
                                                                          x
                                                  Average cost AC =      2 .
                                                                     x
                                   The most economic speed will be that value of x which minimises AC.
                                                          d AC      12800
                                                                =     2   2 0,  for minima or
                                                            dx        x

                                   or                        x 2  =  12800  6400  or x = 80 kms/hour.
                                                                     2

                                   Second order condition
                                                          2
                                                         d AC      25600  0 , when x = 80.
                                                           dx  2  =  x 3
                                   Thus, the second order condition for minima is satisfied.

                                   Coefficients of a Cubic Total Cost Function

                                   Let the cubic total cost function be TC =  ax 3  bx 2  cx  . d  Therefore, the marginal cost function is
                                   given by
                                                                   d TC     2
                                                             MC =        3ax  2bx c
                                                                    dx




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