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Basic Mathematics – I




                    Notes          Differentiating w.r.t. x, we get
                                                             d      1 k  k  1  1 k
                                                             dx  =   .  k  x   2ax b  0,  for maximum profits
                                   Taking limit of the above as k    1, we get

                                        1  k  1  1
                                   lim  k     .x  k  2ax b       0  or  x  b
                                   k  1    k             =  2ax b         2a

                                   The profit at  x  b  2a  will be maximum if

                                                            d  2  = lim  1 k .  k  1  1  x  1 k  1  2a  2a  0
                                                             dx 2  k  1   k     k                  a > 0

                                   (ii)  Since x is positive in  x  p  k ,  > 0.

                                                                            b
                                       Further, b must be negative in order that  x  0  and no restriction is needed for c.
                                                                           2a
                                   (iii)  Since the  elasticity of demand is  k  (constant), we  can find  the supply  function of the
                                       monopolist. The supply function is given by the condition MR = MC. We have
                                                                                   1
                                                                    1  k  1  1     k k  1  k  –1
                                                            MR =    k      x  k    .     p      and MC = 2ax + b
                                                                        k        x   k      k

                                                           k  1                  k  1
                                                         p      = 2ax b  or  2ax  p    b
                                                            k                     k
                                                                     k  1  1  b
                                   or                         x = p              is the required supply function.
                                                                      k   2a  2a

                                          lim    k  1  1  b    b
                                   Since   x  k  1  p  k  2a  2a  2a ,  this supply function is consistent with the answer to part (i).


                                                                                   1
                                                                                     2
                                          Example: A monopolist with the cost function C(x) =  x  faces a demand curve  x  12 p.
                                                                                   2
                                   (i)  What will be his equilibrium price and quantity?
                                   (ii)  If for some reason the firm behaves as though it were in a perfectly competitive industry,
                                       what will equilibrium price and quantity be? How much money will the firm require to
                                       forgo monopoly profits and behave competitively instead?
                                   Solution:

                                   (i)           Total revenue TR = px  12 x x  12x x 2

                                                                          1  2     3  2
                                                                        2
                                                         Profit   = 12x x  x  12x   x
                                                                          2        2
                                                             d
                                                                = 12 3x  0  or x = 4 for maximum p.
                                                             dx
                                                            d 2
                                                             dx  2  =  3 0 ,   the second order condition is satisfied.


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