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Basic Mathematics – I
Notes Thus we have
(iii) Prove that
Proof: Draw a circle of radius 1 unit and with centre at the origin O. Let B (1,0) be a point on the
circle. Let A be any other point on the circle. Draw AC OX.
Let AOX = x radians, where 0 < x <
Draw a tangent to the circle at B meeting OA produced at D. Then BD OX.
Area of AOC< area of sector OBA< area of OBD.
2
or OC AC < x(1) < OB BD
×
cos x sin x < x < ∙ 1 ∙ tan x
i.e.,
or
or
i.e.,
Taking limit as x 0, we get
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