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Basic Mathematics – I




                    Notes                 Thus we have



                                   (iii)  Prove that


                                   Proof: Draw a circle of radius 1 unit and with centre at the origin O. Let B (1,0) be a point on the
                                   circle. Let A be any other point on the circle. Draw AC   OX.




















                                          Let  AOX = x radians, where 0 < x <

                                          Draw a tangent to the circle at B meeting OA produced at D. Then BD   OX.

                                          Area of  AOC< area of sector OBA< area of  OBD.
                                                             2
                                          or   OC  AC <   x(1)  <   OB  BD



                                                                                                              ×
                                             cos x sin x <   x <   ∙ 1 ∙ tan x







                                       i.e.,


                                       or


                                       or


                                       i.e.,

                                          Taking limit as x    0, we get








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