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Unit 8: Continuity



                                  2
                                                                            2
               Thus we can say that if x and 2x are two continuous functions at x = a then (x  + 2x) is also  Notes
               continuous at x = a.
                                                                2
                                        2
          4.   Consider the function f(x) = (x  + 1)(x +2). We know that (x  + 1) and (x + 2)  are two
               continuous functions.
               Also          f(x)  =  (x  + 1)(x + 2)
                                     2
                                    3
                                         3
                                 =  x  + 2x  + x + 2
                  3
               As x , 2x , x and 2 are continuous functions, therefore.
                      2
                    2
                3
               x  + 2x  + x + 2 is also a continuous function.
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               We can say that if (x  + 1) and (x + 2) are two continuous functions then (x  + 1)(x + 2) is also
                               2
               a continuous function.
                                                              2
          5.   Consider the function f(x) =   at x = 2. We know that (x  – 4) is continuous at x = 2. Also
               (x + 2) is continuous at x = 2.
               Again              =

                                 =

                                 =  2 – 2 = 0

               Also          f(2)  =


                                 =    = 0

                   f(x) = f(2). Thus f(x) is continuous at x = 2.


                  2
               If (x  – 4) and x + 2 are two continuous functions at x = 2, then    is also continuous.

          6.   Consider the function f(x) =|x – 2|. The function can be written as:

                             f(x)  =

                                 =


                                 =

                                 =  2 – 2 = 0
                                 =
                                                                                   …(i)
                                 =


                                 =  2 – 2 = 0                                     …(ii)
               Also          f(2)  =  (2 – 2) = 0                                 …(iii)
               From (i), (ii) and (iii),




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