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          E L-LOVELY-H math5-1     IInd  6-8-11     IIIrd  24-1-12     IVth  21-4-12     Vth  20-8-12     VIth 10-9-12






                                                                          fJekJh^5 L d{i/ ns/ T[Zuso eqw d/ fBy/VB

                                                     y 1  = [cos (sin x)]. cos x                                          HHHH(1)   B'N

                d[pkok fBy/VB eoB s/






                                        2
                fJ; soQK y 2  + y 1  tan x + y cos  x = 0 H
                                    ax
                T[dkjoD 4H i/eo y = e  sin bx j't/ sK f;ZX eo' fe
                                      2
                                     d y     dy
                                                  2
                                           − a  +( a +a y = 0
                                                      2
                                          2
                                                       )
                                     dx 2    dx
                                     ax
                jZb L fdZsk j?,      y = e  sin bx                                                       HHH(1)
                x d/ ;kg/y fBy/VB eoB s/,






                                                                                                        HHH(2)


                x d/ ;kg/y d[pkok fBy/VB eoB s/,












                                                                         ;wheoD (1) ns/ (2) s'A
                          2
                         d y    dy
                fJ; soQK    -  2  +(a +a )y = H
                                     2
                                         2
                                              0a
                         dx 2   dx

                ;t?^w[bKeD (Self Assessment)
                1H ykbh ;EkBK dh g{osh eo' (Fill in the blanks)^
                      d   dy 
                 (i)        y  dk HHHHHHHHHHHHHH fBy/VB^r[DKe efjzd/ jB.
                        
                     dx dx 
                      d  dy                          d             dy
                          2
                                                                      2
                 (ii)     2   HHHHHHHHHHHHH                 (iii)   (HHHHHHHHHHHHH) =  H
                     dx dx                            dx            dx 2
                        


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