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bdkbZ—13% lk/kj.k izrhixeu xq.kkad fof/




            gy (Solution): y osQ fn, gq, ewY;ksa dks x osQ y ij lehdj.k esa rFkk x osQ ewY;ksa dks y osQ x ij lehdj.k esa  uksV
            vkfn"V djus ij Øe'k% x vkSj y osQ laxf.kr ewY; x  o y  fudky fy, tk;saxs fiQj fuEufyf[kr lkj.kh cukbZ
                                                  c
                                                      c
            tk,xhμ
                                    vuqeku&izeki =kqfV (U;wure oxZ jhfr)

                    U;wure oxZ jhfr  fopyu     fopyu                     fopyu
              x     }kjk xf.kr ewY;  (x – x )  (x – x ) 2  y      y      (y – y )  (y – y ) 2
                                         c         2               c         c         c
                    x  = 0.5 + 0.5y
                     c
              1           .5         – 0.5       0.25      2      2.4    – 0.4      0.16
              2          3.0         – 1.0       1.00      5      3.7      1.3      1.69
              3          2.0         + 1.0       1.00      3      5.0    – 2.0      4.00
              4          4.5         – 0.5       0.25      8      6.3      1.7      2.89
              5          4.0         + 1.0       1.00      7      7.6    – 0.6      0.36
                                                 3.50                               9.10

                             Σ(x −  x  ) 2  . 350                Σ(y −  y  ) 2  . 910
                      S  =         c   =                  S  =         c   =
                       xy
                                 N         5               yx        N         5
                              .
                      S xy  =  070  = .84                 S =  182.   = 1.35
                                                           yx
            iznÙk lehdj.kksa ls ekè;&ewY; izrhixeu Kkr djuk (Find the mean-value Regression by
            given Equation)
            xq.kkadksa dh x.kukμ;fn nksuksa izrhixeu lehdj.k Kkr gksa rks mudks gy djosQ x vkSj y osQ ekè; (x  o  y )

            fudkys tkrs gSaA ijUrq x osQ y ij lehdj.k ls bxy vkSj y osQ x ij lehdj.k ls byx Hkh Kkr fd;s tk ldrs gSaA
            ijUrq dHkh&dHkh lehdj.k bl izdkj fn, tkrs gSa fd muosQ fujh{k.k ls ;g fuf'pr ugha fd;k tk ldrk gS
            fd muesa ls dkSu&lk x dk y ij vkSj y dk x ij izrhixeu izLrqr djrk gSA ,slh fLFkfr esa fdlh ,d dks x
            dk y ij izrhixeu lehdj.k ekudj byx Kkr dj fy;k tkrk gS vkSj blh izdkj nwljs lehdj.k dh lgk;rk
            ls byx fudky fy;k tkrk gSA ;fn bxy vkSj byx dk xq.kuiQy 1 ls vfèkd gS rks gekjh ifjdYiuk xyr gS D;ksafd
            2
            r  > 1. ;fn ,slk gks rks iz'u dks fiQj ls gy djuk iM+rk gSA bl ckj ml lehdj.k dks Y dk X ij lehdj.k
            ekuuk gksxk ftls igys X dk Y ij ekuk FkkA bl izdkj byx vkSj bxy dh xq.kk 1 ls vfèkd ugha gksxh vkSj ifj.kke
            'kq¼ gksaxsA
            mgkgj.k (Illustration) 10: ;fn nks izrhixeu lehdj.k fuEu izdkj gksa rks x o y osQ ekè; ewY; fudkfy, vkSj
            lg&lEcUèk xq.kkad fudkfy,μ
                               4y – 15x + 530 = 0
                               20x – 3y – 975 = 0
            gy (Solution)% x o y osQ ekè; ewY;
                             4y – 15x ± – 530                                          ...(1)
                                  – 3y + 20x = 975                                     ...(2)

            leh- (1) esa 3 rFkk leh- (2) esa y dk xq.kk djus ij]
                                  12y – 45x = – 1590
                                  – 12y + 80x = 3900
                                        35x = 2310




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