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bdkbZμ5 % ekè;] ekfè;dk rFkk cgqyd osQ vuqiz;ksx
fd;k tkrk gSA uksV
fof/&(i)μ loZizFke izR;sd fopyu ;k in&fopyu eas 1 tksM+dj (dx +1) vFkok (d'x+1) Kkr dj fy;k tkrk
gSA
(ii) (dx + 1) ;k (d'x+1) esa mudh vko`fÙk;ksa dh xq.kk djosQ xq.kuiQyksa dk ;ksx Σ[f(dx+1] vFkok Σ[f(d'x+1)]Kkr
dj fy;k tkrk gSA
(iii) rRi'pkr~ fuEu lehdj.kksa dk iz;ksx fd;k tkrk gSμ
Σfdx = Σ[f(dx+1)]–Σf y?kq jhfr dk iz;ksx djus ij
Σfd'x = Σ[f(d'x+1)]–Σf in&fopyu jhfr dk iz;ksx djus ij
(iv) ;fn mi;ZqDr lehdj.k osQ nksuksa i{k cjkcj gSa] rks le> ysuk pkfg, fd x.ku&fØ;k 'kq¼ gS vU;Fkk dksbZ
=kqfV gks xbZ gSA
lekos'kh oxkZUrj fdls dgrs gSa\
mnkgj.k (Illustration) 6: fuEu lkj.kh ls ekè; fudkfy,
oxZ: μ10 10μ20 20μ30 30μ40 40μ50 50μ60 60μ70 70μ80
vko`fÙk : 22 38 54 75 72 64 31 10
gy (Solution) : pw¡dh iwjh lead&ekyk esa oxZ&foLrkj (10) leku gSA vr% vfUre oxZ dh mQijh lhek 70
+ 10 = 80 ekuh tk;sxh vFkkZr~ ;g oxZ 70μ80 gksxk vkSj igyk oxZ 0μ10 gksxkA
X M.V. f d'x = A–35/10 fd'x (d'x+1) f(d'x+1)
0–10 5 22 – 3 – 66 – 2 – 44
10–20 15 38 – 2 – 76 – 1 – 38
20–30 25 54 – 1 – 54 0 0
30–40 35 75 0 0 +1 + 75
40–50 45 72 + 1 + 72 +2 + 144
50–60 55 64 + 2 +128 +3 + 192
60–70 65 31 + 3 + 93 +4 + 124
70–80 75 10 + 4 + 40 +5 + 50
366 137 503
[N = Σf = 366, A = 35, Σfd'x = 137] [Σf (d'x +1)= 503]
Σfd' x 137
+
=X + A × = i 35+ × 10 = 35 3 74 = . 38 74
.
N 366
pkfyZ;j tk¡p lw=k dk iz;ksx djs ijμ
Σfd'x = Σ[f(d'x + 1)] – Σf or 137 = 503 – 366
∴ 137 = 137 vr% x.kuk&fØ;k esa dksbZ v'kqf¼ ugha gSA
(7) vKkr ewY; ;k vko`fÙk dk fu/kZj.k (Location of Missing Size of Frequency)μ lekUrj ekè; dh
,d egRoiw.kZ fo'ks"krk ;g gS fd ;fn fdlh Js.kh osQ bu rhu ekuksa X,N vkSj ΣX esa dksbZ ls nks eku Kkr
LOVELY PROFESSIONAL UNIVERSITY 63