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bdkbZμ5 % ekè;] ekfè;dk rFkk cgqyd osQ vuqiz;ksx




            (ii) fiQj] izR;sd in&ewY; esa ls dfYir&ekè; fopyu izkIr dj fy;s tkrs gSa vFkkZr~ dx = (X – A)A  uksV
            (iii) izR;sd fopyu (dx) dks mldh vko`fÙk (f) ls xq.kk djosQ] mu xq.kkvksa dk tksM+ fudky fy;k tkrk gSA
            (Σfdx)A

            (iv) vUr esa] fuEu lw=k dk iz;ksx fd;k tkrk gSμ
                   Σfdx            Σfdx
              =X  + A   or    =X  + A
                    N              Σf
            A = dfYir ekè;] Σfdx = fopyuksa o vko`fÙk;ksa dh xq.kkvksa dk tksM+]
            N = vko`fÙk;ksa dk tksM+]
            mnkgj.k (Illustration) 2: fuEufyf[kr [kf.Mr Js.kh esa (i) 15 dks 'kwU; (vFkkZr~ dfYir&ekè;) lekUrj ekè;
            fudkfy;s rFkk (ii) izR;{k jhfr }kjk ifj.kke dh tk¡p dhft,μ

            vkdkj (X)% 20    19     18    17     16    15     14   13    12    11
            vko`fÙk (f)%  1  2      4     8      11    10     7    4     2     1
            gy (Solution) : ;gk¡ dfYir&ekè; 15 ekuk tk,xk D;ksafd iz'u esa fn;k gqvk gSA
                             izR;{k rFkk y?kq jhfr }kjk lekUrj ekè; dk ifjdyu\


                  vkdkj             vko`fÙk               y?kq jhfr           izR;{k jhfr
                                           A = 15 ls fopyu     xq.kuiQy
                (X)           (f)          (dx)                (fdx)           (fX)
                20            1            + 5                 + 5             20
                19            2            + 4                 + 8             38
                18            4            + 3                 + 12            72
                17            8            + 2                 + 16            136
                16            11           + 1                 + 11            176
                15            10           0                   0               150
                14            7            –1                  –7              98
                13            4            –2                  –8              52
                12            2            –3                  –6              24
                11            1            –4                  –4              11
                Total         N = 50                           Σfdx = 27       ΣfX = 777



              y?kq jhfr (Short-cut Method)                 izR;{k jhfr (Direct Method)


                                                           Mean or

                  = 15 + 0.54 = 15. 54                     ∴             X   = 15.54

            (C) v[kf.Mr Js.kh esa eè;d dk ifjdyu (Mean in Continuous  Series)

            v[kf.Mr Js.kh esa lekUrj ekè; Bhd mlh izdkj fu/kZfjr fd;k tkrk gS ftl izdkj [kf.Mr Js.kh esa lw=k Hkh nksuksa
            esa ,d leku gSA ijUrq vUrj osQoy bruk gS fd v[kf.Mr Js.kh esa igys oxks± osQ eè;&ewY; (mid-values) fudkys
            tkrs gSa ftUgsa 'X' dgrs gSaA bl izdkj eè;&ewY; ysus ij v[kf.Mr Js.kh] [kf.Mr Js.kh dk :i ys ysrh gSA


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