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P. 355
Unit 29: The Lebesgue Integral of Bounded Functions
A function : E is said to be simple if there exists a , a ,...., a Î and E , E ,...., E E Notes
1 2 n 1 2 n
n
such that = å i 1 a i E . Note that here the E ’s are implicitly assumed to be measurable, so
=
i
i
a simple function shall always be measurable. We have another characterization of simple
functions:
A function : E is simple if and only if it takes only finitely many distinct values a ,
1
–1
a , .... a and {a } is a measurable set for all i = 1, 2,....., n.
2 n i
)
(a) A ò ( + = A ò + A ò (Note that + ÎS (E) too by the vector space structure
0
(b) A ò a = a for all a Î . (Note aÎS (E) again.)
A ò
0
(c) If a a.e. on A then ò A ò .
A
(d) If = a.e. on A then ò = A ò .
A
(e) If 0 a.e. on A and ò = , then = 0 a.e. on A.
0
A
(f) A ò A ò | |.(Note| | So (E) too.Why?)
Î
Bounded Convergence Theorem Suppose m(E) < , and {f } is a sequence of measurable
n
functions defined and uniformly bounded on E by some constant M > 0, i.e.
|f | M for all n on E.
n
29.5 Keyword
Bounded Convergence Theorem: Suppose m(E) < , and {f } is a sequence of measurable functions
n
defined and uniformly bounded on E by some constant M > 0, i.e.
|f | M for all n on E.
n
29.6 Review Questions
1. Show that if A, B E, A Ç B = 0 / and Î S (E), then ò = A ò + .
0 A B B ò
È
2. Show that if Î S (E) vanishes outside F, then ò = ò for any A E.
Ç
0 A A F
3. Show that if A B E and 0 Î S (E), then ò .
0 A B ò
4. Find an example to show that the assumption m(E) < cannot be dropped in the Bounded
Convergence Theorem.
5. Prove or disprove the following: Let E be of finite or infinite measure. If {f } is a sequence
n
of uniformly bounded measurable functions on E which vanishes outside a set of finite
measure and converges pointwisely to f Î B (E) a.e. on E, then lim f = f . (Compare
0 E ò n E ò
n
with the statement of the Bounded Convergence Theorem.)
Answers: Self Assessment
1. measurable set 2. finite measurable
3. measurable 4. Riemann integrable
5. |f | M
n
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