Page 350 - DMTH401_REAL ANALYSIS
P. 350

Real Analysis




                    Notes              But the A  Ç B’s are disjoint. So by Lemma we have
                                               i   j
                                                    n m
                                                A ò  =  å å  a m(A Ç B Ç A)
                                                             i
                                                         i
                                                                j
                                                    =
                                                      =
                                                    i 1 j 1
                                                     n m
                                                A ò  =  å å  b m(A Ç B Ç  A)
                                                                 j
                                                             i
                                                         i
                                                    i 1 j 1
                                                     =
                                                      =
                                       and
                                                         n m
                                                      )
                                                A ò  ( +  =  å å  (a +  b )m(A Ç  B Ç A).
                                                                          j
                                                                      i
                                                              i
                                                                 j
                                                         =
                                                          =
                                                        i 1 j 1
                                                    )
                                       Hence  ò  ( +  =  A ò  + 
                                              A
                                                                              n
                                   (b)  If a = 0 the result is trivial; if not, then let  =  å i 1 a  A i be the canonical representation of
                                                                              =
                                                                                 i
                                                         n
                                       . We see that a =  å i 1 aa  A is the canonical representation of a and hence the result
                                                          =
                                                             i
                                                                i
                                       follows.
                                                            )
                                   (c)  Since  ò  -  A ò  =  A ò  ( -   by linearity, it suffices to show  ò f   0  whenever 0 a.e. on
                                             A                                         A
                                       A. This is easy, since if a , a , . . ., a  are the distinct values of f, then
                                                           1  2    n
                                        A ò f  å  a m(f - 1 {a } Ç A) +  å  a m( f - 1 {a } Ç A)   å  a 0 = 0
                                                                                     
                                                                        i
                                                                  i
                                                                                    i
                                               i
                                                      i
                                          {i:a i 0}<         {i:a i 0}        {i:a i 0}<
                                                                                 –1
                                       where the inequality follows from the fact that m(f{a  Ç A}) = 0 for all a  < 0.
                                                                                   i              i
                                   (d)  This is immediate from (c).
                                   (e)  Since it is given that   0 a.e. on A, it suffices to show m({x : (x) > 0} Ç A) = 0.
                                       Suppose not, then there exists a > 0 such that m({x : (x) = a} Ç A) > 0 so  ò   a m ({x : (x)
                                                                                                      
                                                                                                 A
                                       = a}Ç A) > 0. This leads to a contradiction.
                                   (f)  This follows directly from monotonicity since –||    ||.
                                   29.3 Bounded Measurable Functions Vanishing Outside a
                                       Set of Finite Measure
                                   Resembling the construction of the Riemann integral, we define the upper and lower Lebesgue
                                   integrals.
                                   Definition: Let f : E   be a bounded function which vanish outside a set of finite measure. For
                                   any A  C, we define the upper integral and the lower integral of f on A by
                                                ___
                                                ò  f inf {ò A    :f   on A,  Î So(E) }
                                                  =
                                                A
                                                        ì                 ü
                                                 ò  f supí ò    : f    on A, Î So(E)ý
                                                    =
                                                ____ A  î  A              þ
                                   If the  two values agree we denote the common value by  ò A f .  (Again the set A is implicitly
                                   assumed to be measurable so that  A ò   and  ò   make sense.)
                                                                       A
                                   Note that both the infimum and the supremum in the definitions of the upper and lower integrals
                                   exist because f is bounded and vanishes outside a set of finite measure. It is evident that for the
          344                               LOVELY PROFESSIONAL UNIVERSITY
   345   346   347   348   349   350   351   352   353   354   355