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P. 77
Unit 4: Compactness
Notes
æ r(x ) æ r(x )
j ö
jk ö
B x , j ÷ for i > j. This has convergent subsequence x by assumption, so k s.t. B x , .
ç
è 2 ø jk ç è jk 2 ø ÷
This is a contradiction, so the procedure stops.
Self Assessment
Fill in the blanks:
1. T, S compact, U open cover of ............... If s S there exists open V S, s V s.t. T V can
be covered by finite subfamily of U.
2. Let T be compact. Cts ............................ is bdd and attains max and min.
3. Given cover U of metric M, > 0 called ...................... of U if " x M U U s.t. B(x, ) U.
4.8 Summary
Let F F ... sequence of non-empty closed subsets of compact T. Then ¥ F . Let F
=
1 2 k 1 k 1
F ... sequence of non-empty compact subsets of Hausdorff T. Then ¥ F .
=
2 k 1 k
" x T find W U s.t. (x, s) W . Exists open U T, V S s.t. (x, s) U V W .
x
x
x
x
x
x
x
{U : x T} open cover of T so U ,..., U which cover T. Let V = n i 1 V . V S open and
x x1 xn = xi
n n
T V U V xi W xi
xi
i 1 i 1
=
=
Let x ¥ j 1 {x , x ...}. k j s.t. x x. k ¥ so can choose subsequence k s.t. k > k ji
=
j
+
j 1
ji
kj
j
ji+1
j
(as ks not necessarily in order). Then x subsequence converging to x.
j kji
Let x M, F = {x , x ...}. F form decreasing sequence of non-empty closed subsets of M.
+
k j j j 1 j
¥ j 1 F so x have convergent subsequence.
=
k
j
4.9 Keywords
Space Compact: Cts image of compact space compact.
Homeomorphism: Cts bijection of compact T onto Hausdorff S is homeomorphism.
Lebesgue Number: Every open cover U of compact metric space has a Lebesgue number.
Convergent Subsequence: Metric M is compact iff every sequence in M has convergent subsequence.
4.10 Review Questions
1. Discuss the compactness of a set.
2. Explain intersection of closed set.
3. Discuss compactness and Continuity.
4. Describe sequential compactness.
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