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Unit 3: Elementary Functions





                                             I                                                  Notes
                                                      i t
                                                      
                                      i LI      RI   ae ,or
                                       
                                            i C
                                            
                                               b
                                        i Lb       Rb  a
                                         
                                              i C
                                               
          Thus,
                                                 a
                                         b 
                                              i  
                                           R     L  1  
                                                    C 
          In polar form,
                                                a
                                                         i
                                      b               2  e ,
                                              
                                                L
                                            2
                                          R      1  
                                              
                                                   C 
          where
                                                  1
                                              L 
                                       tan      C  (R  0)
                                                R
          Hence,
                                                                
                                                   a            
                                      i t
                                                                )
                                                              
                               I  Im(be ) Im            2  e i( t  
                                        
                                      
                                                  
                                                    L
                                                2
                                              R     1       
                                                              
                                                      C      
                                        a
                                     =         2  sin( t   )
                                                   
                                       
                                    2
                                         L
                                   R     1  
                                       
                                            C 
          This result  is well-known  to all,  but it  is hoped  that you  are convinced  that this  algebraic
          approach afforded us by the use of complex numbers is far easier than solving the differential
          equation. You  should note  that this  method yields  the steady  state solution—the  transient
          solution is not necessarily sinusoidal.
          3.2 Trigonometric Functions
          Define the functions cosine and sine as follows:
                                                e  + e –iz
                                                iz
                                         cos z =      ,
                                                  2
                                                 iz
                                                e  – e –iz
                                          sin z =
                                                  2i
          where we are using e  = exp(z).
                           z
          First, let’s  verify that these are  honest-to-goodness extensions of the  familiar real  functions,
          cosine and sine–otherwise we have chosen very bad names for these complex functions.




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