Page 350 - DMTH402_COMPLEX_ANALYSIS_AND_DIFFERENTIAL_GEOMETRY
P. 350
Unit 28: Local Intrinsic Geometry of Surfaces
j
j
i
i
Proof. Denoting the coordinates on U by u and the coordinates on U by u , we let u / u , Notes
j
i
and we find, by the chain rule:
i
j
i
f y f y ( f) f .
Y i j i d Y
z
,
i
i
We define the commutator of two tangent vector fields Y y and Z Equation (5):
i
i
i
i
[Y,Z] y z i j z d y j . j ...(6)
i
Note that
[Y,Z] f Z f Y f. ...(7)
Y
Z
This observation together with Proposition 3.1 are now used to show that the commutator is
reparametrization invariant.
Proposition 2. Let Y and Z be vector fields on U, and let : U U be a diffeomorphism, then
d d Y , d Z .
Y,Z
Proof. For any smooth function f on U, we have:
)
)
f (f (f (f ) ...(8)
Y,Z
d Y,Z Y Z Z Y
f f f f f,
d Z
Y d Z Z d Y d Y d Z d Y d Y ,d Z
and the proposition follows.
We note for future reference that in the proofs of propositions 1 and 2, only the smoothness of
the map is used, and not the fact that it is a diffeomorphism. The operator Z Y Z [Y,Z],
also called the Lie derivative, is a differential operator, in the sense that it is linear and satisfies
a Leibniz identity: Y (fZ) Y f Z f Y Z. However, Y Z depends on the values of Y in a
neighborhood of a point as can be seen from the fact that it is not linear over functions in Y , but
rather satisfies fY Z f Y Z Z f Y. Hence the Lie derivative cannot be used as an intrinsic
directional derivative of a vector field Z, which should only depend on the direction vector Y at
a single point .
1
28.3 Covariant Differentiation
Definition 3. Let (U, g) be a Riemannian metric, and let Z be a vector field on U. The covariant
derivative of Z along is:
i
i Z z i j j ik z k . j ...(9)
1 Indeed Y Z as defined does depend only on the value of Y at a single point and satisfies fY Z f Y Z.
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