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Unit 6: Cauchy’s Integral Formula





                                         2                                                 Notes
                                3 z(s z) 2( z) 
                            =          2    3  g(s)ds
                                           
                                  
                              C  (s z   z) (s z)  
          Hence,
                                         3 z(s z) 2( z) 
                   
           G'(z   z) G'(z)   2  g(s)  ds  =            2  g(s)ds
                                         
                                                 2
                  z        C (s z) 3  C  (s z   z) (s z) 3  
                                                    
                              
                                           
                                        
                              z  ( 3m  2 z )M ,
                                         2
                                   (d   z) d 3
          where m = max {|s – z| : s  C}. It should be clear then that
                                            
                                lim  G'(z   z) G'(z)   2   g(s)  ds  0,
                                                       
                                 z 0     z       C (s z) 3
          or in other words,
                                                  g(s)
                                        G''(z)   2   3 ds.
                                                  
                                               C (s z)
          Suppose f is analytic in a region D and suppose C is a positively oriented simple closed curve in
          D. Suppose also the inside of C is in D. Then from the Cauchy Integral formula, we know that
                                                  f(s)
                                          
                                         2 if(z)    ds
                                                   
                                                C s z
          and so with g = f in the formulas just derived, we have
                                   1    f(s)             2   f(s)
                             f'(z)        ds, and f''(z)     ds
                                  2pi (s z) 2           2 i (s z) 3
                                                              
                                        
                                                         
                                     C
                                                           C
          for all z inside the closed curve C. Meditate on these results. They say that the derivative of an
          analytic function is also analytic. Now suppose f is continuous on a domain D in which every
                                                        0
          point of D is an interior point and suppose that  f(z)dz   for every closed curve in D. Then we
                                                
                                                C
          know that f has an antiderivative in D—in other words f is the derivative of an analytic function.
          We now know this means that f is itself analytic. We thus have the celebrated Morera’s Theorem:
                                                 0
          If f : D  C is continuous and such that  f(z)dz   for every closed curve in D, then f is analytic
                                          
                                          C
          in D.
                 Example:
          Let’s evaluate the integral

                                               e z  dz,
                                               z 3 
                                             C
          where C is any positively oriented closed curve around the origin. We simply use the equation

                                              2    f(s)
                                        f''(z)       ds
                                             2 i (s z) 3
                                                   
                                              
                                                C

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