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Abstract Algebra                                              Sachin Kaushal, Lovely Professional University




                    Notes                            Unit 23: Division of Algorithm




                                     CONTENTS
                                     Objectives

                                     Introduction
                                     23.1 The Division Algorithm
                                     23.2 Summary
                                     23.3 Keywords
                                     23.4 Review Questions

                                     23.5 Further Readings



                                   Objectives

                                   After studying this unit, you will be able to:
                                       Prove and use the division algorithm for F[X], where F is a field
                                   
                                       Discuss examples related to algorithms
                                   
                                   Introduction


                                   In the last unit, you have  studied about polynomials rings.  In this unit, we will discuss the
                                   division of  algorithm.

                                   23.1 The Division Algorithm

                                   We have discussed various properties of divisibility in Z. In particular, we proved the division
                                   algorithm for integers. We will now do the same for polynomials over a field F.
                                   Theorem 1 (Division Algorithm): Let F be a field. Let f(x) and g(x) be two polynomials in F[x],
                                   with g(x)  0. Then

                                   (a)  there exist two polynomials q(x) and r (x) in F [X] such that
                                       f (x) = q (x) g (x) + r (x), where deg r(x) < deg g (x).
                                   (b)  the polynomials q (x) and r (x) are unique.

                                   Proof: (a) If deg f (x) < deg g (x), we can choose q (x) = 0.
                                   Then f(x) = 0. g(x) + f (x), where deg f(x) < deg g (x).
                                   Now, let us assume that deg f(x)  deg g (x).
                                   Let f(x) = a  + a x + . . . +a x , a,  0, and
                                                        n
                                               1
                                                       n
                                           0
                                          g(x) = b  + b x + ... + b x , b   0, with n  m.
                                                         m
                                                       m
                                            0
                                                1
                                                            m


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