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Unit 15: Simultaneous Triangulation and Simultaneous Diagonalization
2. Let be a commuting family of 3 × 3 complex matrices. How many linearly independent Notes
matrices can contain? What about the n × n case?
15.2 Summary
In this unit we are dealing with matrices that commute with each other.
In a triangular matrix the main diagonal has the entries of the characteristic values and it
has not zero entries in the upper part of the diagonal only or non-zero entries in the lower
of the main diagonal.
If two or more matrices commute then we can diagonalize them simultaneously.
15.3 Keywords
Diagonalizable: Each operator in is diagonalizable, because its minimal polynomial divides
i
the minimal polynomial for the corresponding operator in .
Ordered Basis: There exists an ordered basis for V such that every operator in is represented
by a triangular matrix in that basis.
15.4 Review Question
1. Let T be a linear operator on a n-dimension space and suppose that T has n distinct
characteristic values. Prove that any linear operator which commutes with T is a polynomial
in T.
Answers: Self Assessment
1 2 1 1
1. (a) P , (b) P
0 1 1 1
2. 3, n
15.5 Further Readings
Books Kenneth Hoffman and Ray Kunze, Linear Algebra
I.N. Herstein, Topics in Algebra
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