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Differential and Integral Equation




                    Notes          Differentiate (1) with respect to x we have
                                                              p = a                                        ...(3)
                                   Also differentiate (1) with respect to y we have

                                                              z
                                                                 = q = b                                   ...(4)
                                                              y
                                   Substituting the values of a and b from (3) and (4) into the equation (1) we have
                                                                           2
                                                               z = px + qy + p  + q 2                      ...(2)
                                   so equation  (1) having  two arbitrary constants  a and  b  is  the  complete  integral  of partial
                                   differential equation (2).
                                   Differentiating (1) with respect to a and b respectively,

                                   we get
                                                                0  x  2a
                                   and                                                                     ...(5)
                                                                0  y  2b
                                   Substituting the values of a and b in (1) we have

                                                                     x 2  y 2  x  2  y 2
                                                              Z =
                                                                      2  2   4   4
                                                                         2
                                                                      2
                                                             4Z =   (x  + y )                              ...(6)
                                   To see whether equation (6) satisfies (2) we have
                                                                4p   2x
                                                                4q  2y

                                   Substituting in R.H.S. of (2) we have
                                                  x 2  y 2  x 2  y 2  (x 2  y 2  )
                                                                 =           z  L.H.S.
                                                  2   2   4  4          4
                                   So equation (6) satisfies equation (2).

                                   Equation (6) represents a paraboloid of revolution, the envelops of all the planes represented by
                                   the complete integral. Equation (6) represents singular integral.


                                          Example 2: Show that
                                                                        2
                                                              Z = be ax + a y                              ...(1)
                                   is the complete integral of partial differential equation

                                                              p 2  = zy                                    ...(2)
                                   Differentiating (1) w.r.t. x, y respectively

                                                           z          ax+a y
                                                                        2
                                                              p = bae                                      ...(3)
                                                           x
                                                           z             2
                                                                     2
                                                              q  = ba e  ax+a y                            ...(4)
                                                           y

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