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Differential and Integral Equation




                    Notes          The coefficients B   are given by
                                                 n
                                            2  L     n x
                                                 x
                                        B n    f  ( )sin  dx
                                            L  0      L
                                                                      L /2
                                                                 n x
                                                              cos
                                         2A  L /2  n x    2A      L
                                                sin   dx
                                          L  0     L      L   (n  / )
                                                                  L
                                                                      0
                                         2A       n
                                              cos
                                          n       2
                                   or

                                            2A       n
                                        B n    1 cos
                                            n        2L

                                         2A      2 n
                                             2sin
                                          n       4L
                                         4A   2 n
                                            sin                                                           …(10)
                                          n      4L
                                   Thus the solution (9) becomes

                                                      2 n            2 2 2
                                                    sin              n  c t
                                              4A        4L     n x    2
                                        u ( , )            sin     e  L                                   ...(11)
                                           t
                                         x
                                                       n        L
                                                 n  1
                                   So the solution of equation (i) subject to the conditions (A )  and  (A ) is given by equation (11).
                                                                                 1       2
                                   Self Assessment
                                   4.  Find the solution of heat equation.

                                         2    2
                                         V    V    V
                                        dx 2  dy 2  dt

                                       Subject to the boundary conditions
                                                                                       
                                        V  0 when t   , when x  0 or x    and when  y  0 or  .
                                       Also initially
                                           y
                                        V ( , ,0)  f ( , )
                                                  x
                                          x
                                                    y
                                   23.3 Summary
                                      Wave equation is written in Cartesian co-ordinates, cylindrical co-ordinates and spherical
                                       polar co-ordinates.






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