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Unit 23: Wave and Diffusion Equations by Separation of Variable




              It is shown that depending upon the nature of the process the suitable wave equation can  Notes
               be set up and solved.

              One dimensional wave equation suits in most problems. So the solution of wave equation
               in one dimension is solved.
              Two dimensional wave equation depending upon the symmetry of the problem is solved
               both in rectangular and circular cases. Also heat conduction is studied.

          23.4 Keywords

          Heat Conduction: It is an other process that occurs in so many processes. Diffusion process is
          very very similar to conduction process.
          Wave Motion: It can be  obtained in  mechanical vibrations,  electrical  vibrations and  other
          processes.
          23.5 Review Questions


          1.   Show that the solution of the wave equation

                                        1    r 2 u  1  2 v
                                        r  2  r  r  a 2  t  2

               can be of the form

                                           1
                                       r
                                        t
                                     u ( , )  ( t r  at ) F (r  at )
                                           r
               where f and F are arbitrary functions.
          2.   Solve the one dimensional wave equation
                                           2      2
                                            u  1   u
                                                      0
                                                2
                                           x 2  c dt 2
               with the boundary conditions
                                         u (0, )  0
                                            t
                                                  for all t
                                           l
                                         u ( , )  0
                                            t
               and
                                         u(x, 0) = A sin 2x

                                             u
                                                   0
                                              t  t  0
          3.   Solve the heat equation in one dimension:

                                            u    2 V
                                               k     0
                                            t    x 2
               subject to the conditions
                                         u(0, t) = u(, t) =0
                                         and V(x, 0) = sin 3x




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