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Unit 26: The Conjugate Space H*




                          2                                                                     Notes
                     y  y    0
                      1  2
                    y  y
                     1  2
                      is one-to-one.

                              *
          (iii)   is onto: Let f  H . Then   y H such that
                    f(x) = (x,y)

               since f(x) = (x,y) we get
               f = f  so that   y  = f  = f.
                  y             y
                            *
               Hence for  f H ,  a pre-image y H.  Therefore  is onto.
          (iv)   is isometry; let y ,y  H, then
                              1  2
                  y    y     f  f
                   1    2    y   y
                              1  2
                               f y  f
                              1   y
                                   2
               But    f y  f  y  f y  y  y 1  y 2                             (By theorem (1))
                     1   2    1  2
               Hence   y 1   y  2  y 1  y .
                                       2
          (v)  To show   is not linear, let  y H and   be any scalar. Then   ,y  f  y.  Hence for any
               x   H, we get

                    f (x) (x, y)  (x,y)  f (x)
                     y                    y
                    f  y  f y

                       y     y
                      is not linear. Such a mapping is called conjugate linear.
               This completes the proof of the theorem.

               Note: The above correspondence   is referred to as natural correspondence between H and
                *
               H .
          Theorem 4: If H is a Hilbert space, then H  is also an Hilbert space with the inner product defined
                                           *
          by
                                  (f , f ) = (y,x)                                … (1)
                                   x  y
          Proof: We shall first verify that (1) satisfies the condition of an inner product.

          Let  x,y H and  ,  be complex scalars.
          (i)  We know (see Theorem 3) that
               f  y  f y

               f    f    f .
                y    y   y
          Now    f  f ,f   f  f ,f                                                ... (2)
                 x   y  z   x  y  z



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