Page 287 - DMTH505_MEASURE_THEOREY_AND_FUNCTIONAL_ANALYSIS
P. 287

Measure Theory and Functional Analysis




                    Notes
                                   But  f  f ,fz  z, x, y                                                (by (1))
                                        x  y
                                   Now  z, x  y    z,x    z,y

                                                                  f ,f z  f ,f z                          … (3)
                                                    x
                                                           y
                                   From (2) and (3) it follows that   f x  f ,f z  f ,f z  f ,f z
                                                                                 y
                                                                  y
                                                                          x
                                   (ii) f ,f  y,x  x,y  f ,f .
                                       x  y             x  y
                                   (iii) f ,f  x,x  x  2  f  2  so f ,f  0 and  f  0  f  0.
                                       x  x            x     x  x       x      x
                                   i    iii  implies that (1) represents an inner product. Now the Hilbert space H is a complete
                                   normed linear space. Hence its conjugate space H  is a Banach space with respect to the norm
                                                                           *
                                   defined on H . Since the norm on H  is induced by the inner product, H  is a Hilbert space with
                                             *
                                                               *
                                                                                            *
                                   the inner product (f , f )  = (y,x)
                                                  x  y
                                   This completes the proof of the theorem.
                                                             *
                                                         **
                                   Cor. The conjugate space H of H is a Hilbert space with the inner product defined as follows:
                                          *
                                                                                 **
                                   If  f,g  H ,let F  and F g  be the corresponding elements of H obtained by the Riesz representation
                                               f
                                   theorem.
                                                                          **
                                   Then (F ,F ) = (g,f) defines the inner product of H .
                                         f  g
                                   Theorem 5: Every Hilbert space is reflexive.
                                                                                     **
                                   Proof: We are to show that the natural imbedding on H and H  is an isometric isomorphism.
                                                                                                 *
                                   Let x be any fixed element of H. Let F  be a scalar valued function defined on H  by F (f) = f(x) for
                                                                x                                    x
                                                                                                **
                                            *
                                   every  f  H .  We have already shown in the unit of Banach spaces that  F x  H . Thus each vector
                                   x H gives rise to a functional F  in H . F  is called a functional on H  induced by the vector x.
                                                                                          *
                                                                 **
                                                             x      x
                                             **
                                   Let  J : H  H be defined by  J x  F  for every x H.
                                                                x
                                                                                                              **
                                   We have also shown in chapter of Banach spaces that J is an isometric isomorphism of H into H .
                                   We shall show that J maps H onto H .
                                                                **
                                                 *
                                   Let  T : H  into  H  defined by
                                       1
                                   T x   f ,f y  y,x  for every y H.
                                    1    x  x
                                                   **
                                   and T : H  *  into  H  defined by
                                       2
                                                             *
                                   T f x  F ,F f  f,f  for f  H .
                                    2
                                                    x
                                             f x
                                          f x
                                   Then T .T is a composition of T and T from H to H . By Theorem 3, T ,T are one-to-one and
                                                                             **
                                        2  1                2     1                          1  2
                                   onto.
                                   Hence T .T  is same as the natural imbedding J.
                                         2  1
                                   For this we show that J(x) = (T .T )x for every  x H.
                                                           2  1
                                   Now (T .T )x = T (T (x)) = T (f ) =  F .
                                         2  1   2  1     2  x  f x
          280                               LOVELY PROFESSIONAL UNIVERSITY
   282   283   284   285   286   287   288   289   290   291   292