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Unit 13: Test of Significance



            5.   The random variate t is defined as the ratio of a standard normal variate to the square root  Notes
                    2
                 of    - variate divided by its degrees of freedom.

                                            X     X    n
                   To show this we can write  t   
                                            s/ n      s
                   Dividing numerator and denominator by , we get


                                   X    n   X      X   
                             t =             / n       / n
                                      s       s /  2  1        X  2
                                              2
                                                               i
                                                            X 
                                                      n 1      2
                                                       
                                   X   

                               =   / n    Standard Normal Variate
                                      2 n 1      2 -variate
                                     
                                   n   1
















            Illustration: There are two nourishment programmes ‘A’ and ‘B’. Two groups of children are
            subjected to this. Their weight is measured after six months. The first group of children subjected
            to the programme ‘A’ weighed 44,37,48,60,41 kgs. at the end of programme. The second group of
            children were subjected to nourishment programme ‘B’ and their weight was 42, 42, 58, 64, 64, 67,
            62 kgs. at the end of the programme. From the above, can we conclude that nourishment
            programme ‘B’ increased the weight of the children significantly, given a 5% level of confidence.

            Null Hypothesis: There is no significant difference between Nourishment programme ‘A’ and
            ‘B’.
            Alternative  Hypothesis:  Nourishment  programme  B  is  better  than  ‘A’  or  Nourishment
            programme ‘B’ increase the children’s weight significantly.
            Solution:

                                 Nourishment programme         Nourishment programme B
                                          A
                   X            x x          x x      y     y y          y y  
                                                 2
                                                                                 2
                                 
                                                                
                               = (x-46)                       =(y-57)
                   44            -2            4       42      -15            225
                   37            -9           81       42      -15            225
                   48            2             4       58       1             1    Contd...
                   60           14            196      64       7             49
                   41            -5           25       64       7             49
                                                               10
                                                                              100
                                             LOVELY PROFESSIONAL UNIVERSITY                                  243

                                                       67
                                                       62       5             25
                  230            0            310      399      0             674
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